To isolate c means to separate it completely on one side of the equals sign.
To isolate variables, you apply opposite operations.
In E = mc², m and c are being multiplied together. To separate them, you divide by the variable you want to get rid of. However, you must do this to both sides of the equation always. Whatever you do to one side of the equation you must do to the other side as well. This is so the equation remains true.
Since we want to isolate c, we'll start by dividing both sides by m.
E = mc²
E/m = mc²/m
E/m = c² -- The m's cancel as 1
Now we have c squared. The opposite of squaring something is taking its square root. Take the square root of each side.
E/m = c²
√(E/m) = √(c²)
√(E/m) = c -- Opposite operations cancel each other out
And you've isolated c!
Answer:
c = √(E/m)
Answer:
3 : (1/2) =
Step-by-step explanation:
Divide: 3 : 
Dividing two fractions is the same as multiplying the first fraction by the reciprocal value of the second fraction. The first sub-step is to find the reciprocal (reverse the numerator and denominator, reciprocal of
is
) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators.
In words - three divided by one half = six.
Answer:1
Step-by-step explanation:
-12 - 8(5)= -52
-6> -52
The correct answer is: [B]: "40 yd² " .
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First, find the area of the triangle:
The formula of the area of a triangle, "A":
A = (1/2) * b * h ;
in which: " A = area (in units 'squared') ; in our case, " yd² " ;
" b = base length" = 6 yd.
" h = perpendicular height" = "(4 yd + 4 yd)" = 8 yd.
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→ A = (1/2) * b * h = (1/2) * (6 yd) * (8 yd) = (1/2) * (6) * (8) * (yd²) ;
= " 24 yd² " .
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Now, find the area, "A", of the square:
The formula for the area, "A" of a square:
A = s² ;
in which: "A = area (in "units squared") ; in our case, " yd² " ;
"s = side length (since a 'square' has all FOUR (4) equal side lengths);
A = s² = (4 yd)² = 4² * yd² = "16 yd² "
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Now, we add the areas of BOTH the triangle AND the square:
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→ " 24 yd² + 16 yd² " ;
to get: " 40 yd² " ; which is: Answer choice: [B]: " 40 yd² " .
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Let William be x years old.
Thomas = (4 + x) years
In five years,
William = (x + 5) years
Thomas = 4 + x + 5 = (9 + x) years
Given, in five years sum of their ages is 24.
x + 5 + 9 + x = 24
2x + 14 = 24
2x = 24 - 14
2x = 10
x =

x = 5
Hence, William is 5 years old and Thomas is 9 years old.