There is no way for multiple buttons to be displayed next to each other in a horizontal arrangement in App Inventor.

Write an if else statement that assigns 0 to the variable b and assigns 1 to the variable c if the variable a is less than 10. O

brilliants [131]

Answer:

if(a < 10)

{ b = 0; c = 1;}

else

{ b = -99; c = 0;}

Explanation:

4 0

3 years ago

There are two kinds of emotions: positive and negative. True False

fgiga [73]

Answer:

False

Explanation:

There are many emotions the human brain can experience

6 0

2 years ago

Read 2 more answers

Using Python I need to Prompt the user to enter in a numerical score for a Math Class. The numerical score should be between 0 a

yaroslaw [1]

Answer:

The program doesn't use comments; See explanation section for detailed line by line explanation

Program starts here

def lettergrade(subject,score):

print(subject+": "+str(score))

if score >= 90 and score <= 100:

print("Letter Grade: A")

elif score >= 80 and score <= 89:

print("Letter Grade: B")

elif score >= 70 and score <= 79:

print("Letter Grade: C")

elif score >= 60 and score <= 69:

print("Letter Grade: D")

elif score >= 0 and score <= 59:

print("Letter Grade: F")

else:

print("Invalid Score")

maths = int(input("Maths Score: "))

english = int(input("English Score: "))

pe = int(input("PE Score: "))

science = int(input("Science Score: "))

arts = int(input("Arts Score: "))

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

Explanation:

The program makes the following assumptions:

Scores between 90–100 has letter grade A

Scores between 80–89 has letter grade B

Scores between 70–79 has letter grade C

Scores between 60–69 has letter grade D

Scores between 0–69 has letter grade E

Line by Line explanation

This line defines the lettergrade functions; with two parameters (One for subject or class and the other for the score)

def lettergrade(subject,score):

This line prints the the score obtained by the student in a class (e.g. Maths Class)

print(subject+": "+str(score))

The italicized determines the letter grade using if conditional statement

This checks if score is between 90 and 100 (inclusive); if yes, letter grade A is printed

if score >= 90 and score <= 100:

print("Letter Grade: A")

This checks if score is between 80 and 89 (inclusive); if yes, letter grade B is printed

elif score >= 80 and score <= 89:

print("Letter Grade: B")

This checks if score is between 70 and 79 (inclusive); if yes, letter grade C is printed

elif score >= 70 and score <= 79:

print("Letter Grade: C")

This checks if score is between 60 and 69 (inclusive); if yes, letter grade D is printed

elif score >= 60 and score <= 69:

print("Letter Grade: D")

This checks if score is between 0 and 59 (inclusive); if yes, letter grade F is printed

elif score >= 0 and score <= 59:

print("Letter Grade: F")

If input score is less than 0 or greater than 100, "Invalid Score" is printed

else:

print("Invalid Score")

This line prompts the user for score in Maths class

maths = int(input("Maths Score: "))

This line prompts the user for score in English class

english = int(input("English Score: "))

This line prompts the user for score in PE class

pe = int(input("PE Score: "))

This line prompts the user for score in Science class

science = int(input("Science Score: "))

This line prompts the user for score in Arts class

arts = int(input("Arts Score: "))

The next five statements is used to call the letter grade function for each class

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

7 0

2 years ago

Assume you are given three variables, revenue, expenses, and profit, all of type Money (a structured type with two int fields, d

Andre45 [30]

Answer:

if(revenue.cents - expenses.cents < 0){

profit.dollars = revenue.dollars - expenses.dollars - 1;

profit.cents = 1 - revenue.cents - expenses.cents;

}

else{

profit.dollars = revenue.dollars - expenses.dollars;

profit.cents = revenue.cents - expenses.cents;

}

Explanation:

We know that profit is given as: revenue - expenses from the question.

From the given expression above;

if(revenue.cents - expenses.cents < 0)

then profit.dollar will be revenue.dollars - expenses.dollars - 1; the 1 is to be carry over to the cent part. And the profit.cent will be 1 - revenue.cents - expenses.cents;

else the profit.dollars and the profit.cent is computed directly without needing to carry over:

profit.dollars = revenue.dollars - expenses.dollars;

profit.cents = revenue.cents - expenses.cents;

7 0

2 years ago

To support an internet client, you must have six elements. the first three -- a computer, an operating system and tcp/ip -- are

UkoKoshka [18]

Client software, Internet connection and Internet address

6 0

2 years ago