The Nurse should include to the instruction is to drink a
full glass of water with each dose and at least 8 more glasses (8 ounces each)
of fluid a day or drink 3000 mL a day. . If your doctor has directed you to
drink less fluid for other medical reasons, Dosage is based on your medical
condition and response to treatment.
Answer: Diagnosis: The presence of nitrites in the urine confirms the urinary tract infection.
Explanation:
Treatment: The urinary tract infection will be concerned with the antibiotic therapy to kill the bacteria producing excess nitrites. Educating K.N. about the risk factors associated with the multiple sex partners and transfer of bacteria through sexual contact.
Use of fluroquinolones and nitrofurantoin:
Fluroquinolones: This is an antibiotic which has bacteriocidal property can be useful in the treatment of urinary tract infections.
Nitrofurantoin: It is an effective antibiotic in killing bacteria it gets activated inside the bacteria.
Nitrituria is a condition in which the nitrites are present in the urine that is indicative of the presence of bacterial infection. It is caused by the <em>E. coli</em> bacteria inside the urinary tract. It is responsible for converting the nitrates into nitrites.
Difference between aquatic animals and terrestrial animal is
Stars are classified based on the spectral type (i.e. a means to measure the photospheric temperature and density by getting information about the ionisation state).
Under the Morgan–Keenan (MK) system using the letters O, B, A, F, G, K, and M, a sequence from the hottest (O type) to the coolest (M type) (Harvard Spectral classification based on the surface temperature of the stars). A luminosity class is added to the spectral class using Roman numerals (Yerkes Spectral classification). This is based on the width of certain absorption lines in the star's spectrum (0 or Ia+ - hypergiants, I - supergiants, II - bright giants, III - regular giants, IV - sub-giants, V - main-sequence stars, sd - sub-dwarfs, and D - white dwarfs).
I think the answer is photosynthesis 2
