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Gelneren [198K]
3 years ago
14

Question 4 of 5

Mathematics
2 answers:
bazaltina [42]3 years ago
7 0

Answer:

42m+12

Step-by-step explanation:

laila [671]3 years ago
3 0

Answer:

the answer is A

Step-by-step explanation:

because 6×7 which would make it 42m and 6×2 is 12 which would be the +12

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T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as
Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is


K(x)= \frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}


The given curve is y=7e^{x}


{y}''=7e^{x}\\ {y}'=7e^{x}


k(x)=\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}


{k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}

For Maxima or Minima

{k(x)}'=0

7(e^x)(1+49e^{2x})(98e^{2x}-1)=0

→e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0

e^{x}=0  ,  ∧ 1+49e^{2x}=0   [not possible ∵there exists no value of x satisfying these equation]

→98e^{2x}-1=0

Solving this we get

x= -\frac{1}{2}\ln{98}

As you will evaluate {k(x})}''<0 at x=-\frac{1}{2}\ln98

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[-\frac{1}{2}\ln98,1/√2]

k(x)=\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}

k(x)=\frac{7}{\infty}

k(x)=0







5 0
3 years ago
which undefined geometric term can be described as a one dimensional set of point that has no beginning or end?
user100 [1]
A line-----------------
3 0
3 years ago
Read 2 more answers
G(-5) = -4*|(-5)-1|
Mamont248 [21]
There is one answer, -24.

While yes, absolute value does indicate both a positive and negative will work, for every x value there will be only one y value associated with it; if there were more, then it would not meet the criteria to be a function.
7 0
3 years ago
Which statement explains Joni’s error?
USPshnik [31]

Answer:

um can i see the statements?

Step-by-step explanation:


8 0
3 years ago
A shipping company claims that 95% of packages are delivered on time. A student wants to conduct a simulation
NISA [10]

The average number of packages the led to be selected in order to find a package that was not delivered on time is 2.2 option first is correct.

<h3>What is simple random sampling?</h3>

With simple random sampling, each component of the population has an equal chance of being selected for the sample.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have:

A shipping company claims that 95% of packages are delivered on time.

From the table:

00- 04 is the package not delivered on time.

05-99 - package delivered on time.

The first simulation's third number, 31, 64, 04, is where you can locate an item that wasn't delivered on time.

The second simulation's second number, 34, 02, is the location of a late-delivered delivery.

The third simulation is equal to 96,00 - the second number, which is the location of a late package.

The second number where to find a shipment not delivered on time in the fourth simulation is 31,04

Where to find a box that wasn't delivered on time in the fifth simulation: 98, 01, second number

The average number = (3 + 2 + 2 + 2 + 2)/5

= 11/5

= 2.2

Thus, the average number of packages the led to be selected in order to find a package that was not delivered on time is 2.2 option first is correct.

Learn more about the simple random sampling here:

brainly.com/question/13219833

#SPJ1

5 0
1 year ago
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