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Afina-wow [57]
2 years ago
9

Find the magnetic force experienced by a proton moving with the speed of 3 × 105 m/s in the magnetic field B of magnitude 6 × 10

-5 T.
Chemistry
1 answer:
Karo-lina-s [1.5K]2 years ago
6 0

The magnetic force experienced by a proton moving with a speed of 3 ×10^{5} m/s in the magnetic field B of magnitude 6 ×10^{-5} T will be 2.88×10^{-18} N.

Magnetic force can be defined as the attraction or repulsion force that arises between electrically charged particles due to the motion of the charged particles.

Given,

Speed = 3×10^{5} m/s

Magnetic Field, B= 6 ×10^{-5} T

Magnetic force is the product of velocity, the charge of a proton, and the magnetic field present there.

The magnetic force can be represented as:

F=qvB

F=1.6×10^{-19}×3×10^{5} ×6 ×10^{-5}

F=2.88×10^{-18} N

Hence, the magnetic force experienced by the proton will be 2.88×10^{-18} N.

Learn more about Magnetic force here:

brainly.com/question/25932320

#SPJ10

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