Question

Find the magnetic force experienced by a proton moving with the speed of 3 × 105 m/s in the magnetic field B of magnitude 6 × 10-5 T.

Answer 1

The magnetic force experienced by a proton moving with a speed of 3 ×$10^{5}$ m/s in the magnetic field B of magnitude 6 ×$10^{-5}$ T will be 2.88×$10^{-18}$ N.

Magnetic force can be defined as the attraction or repulsion force that arises between electrically charged particles due to the motion of the charged particles.

Given,

Speed = 3×$10^{5}$ m/s

Magnetic Field, B= 6 ×$10^{-5}$ T

Magnetic force is the product of velocity, the charge of a proton, and the magnetic field present there.

The magnetic force can be represented as:

F=qvB

F=1.6×$10^{-19}$×3×$10^{5}$ ×6 ×$10^{-5}$

F=2.88×$10^{-18}$ N

Hence, the magnetic force experienced by the proton will be 2.88×$10^{-18}$ N.

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