What pressure is required to compress 196.0 liters of air at 1.83 atmosphere into a cylinder whose volume is 26.0 liters
1 answer:
Answer:
P₂ = 13.79 atm
Explanation:
Given data:
Initial volume = 196.0 L
Initial pressure = 1.83 atm
Final volume = 26.0 L
Final pressure = ?
Solution:
The given problem will be solved through the Boyle's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
1.83 atm × 196.0 L = P₂× 26.0 L
P₂ = 358.68 atm. L / 26.0 L
P₂ = 13.79 atm
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