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3 years ago

In a class of 23 student the girls were 7 more than the boys how many boys were in the class

Mathematics

1 answer:

Softa [21]3 years ago

5 0

Answer:

x=# of boys

x+7=# of girls

x+x+7=25

2x+7=25

2x=25-7

2x=18

x=18/2

x=9 boys

x+7=16 girls

If you don't understand variables use trial and error.

Boys Girls

1 8

2 9

3 10

4 11

5 12

6 13

7 14

8 15

9 16 9+16=25 students

You could start this way...

Boys Girls

12 13

11 14

10 15

9 16 16 is 7 more than 9

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3 years ago

A parallelogram has sides 10m and 12m and an angle of 45°. Find the distance between the 12m-sides.

stich3 [128]

Answer:

The distance between 12m-sides is $5\sqrt{2}m$ .

Step-by-step explanation:

It is given that the parallelogram has sides 10m and 12m and an angle of 45°.

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The opposite angles of parallelogram are same. Two angles are obtuse angles and two are acute angle.

Since angle C is acute angle therefore it must be 45 degree.

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3 years ago

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3 years ago

How to find the perimeter of a semicircle

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3 years ago

Someone please help I don’t understand this please

sdas [7]

The fraction of the image in blue with respect to the <em>entire</em> hexagon is $\frac{1}{3}$ .

<h3>Estimation of the ratio of the shaded region area to the entire area</h3>

Initially we proceed to create auxiliar constructions , represented by red line segments, to re-define the hexagon as a sum of standard figures. According to the figure, we find two types of triangles (type-1 and type-2), and the following relationship between the two types:

$A_{1} = A_{2}$ (1)

Where:

$A_{1}$ - Area of a type-1 triangle.
$A_{2}$ - Area of a type-2 triangle.

The formulae for the area of the shaded region ( $A_{s}$ ) and the <em>entire</em> hexagon ( $A_{h}$ ) are, respectively:

<h3>Shaded region</h3>

$A_{s} = 2\cdot A_{1} + 4\cdot A_{2}$ (2)

<h3>Entire hexagon</h3>

$A_{h} = 8\cdot A_{1} + 10\cdot A_{2}$ (3)

And the fraction of the image in blue is:

$\frac{A_{s}}{A_{h}} = \frac{2\cdot A_{1}+4\cdot A_{2}}{8\cdot A_{1}+10\cdot A_{2}}$

$\frac{A_{s}}{A_{h}} = \frac{6\cdot A}{18\cdot A}$

$\frac{A_{s}}{A_{h}} = \frac{1}{3}$

The fraction of the image in blue with respect to the <em>entire</em> hexagon is $\frac{1}{3}$ . $\blacksquare$

To learn more on hexagons, we kindly invite to check this verified question: brainly.com/question/4083236

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2 years ago

In a class of 23 student the girls were 7 more than the boys how many boys were in the class​

In a class of 23 student the girls were 7 more than the boys how many boys were in the class