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Elena-2011 [213]
3 years ago
8

A used bookstore will trade 2 of its books for 3 of yours. If Val brings in 18 books to trade, How many books can she get from t

he store?
Mathematics
2 answers:
dolphi86 [110]3 years ago
8 0

Answer:

She will get 12 books from the store

Step-by-step explanation:

We can use ratio's to solve

2 books out      x books out

------------------- =-----------------------------

3 books in          18 books in from Val


Using cross products

2 * 18 = 3 *x

Divide each side by 3

2*18 /3 = 3x/3

2*6 = x

12 =x

She will get 12 books from the store

Molodets [167]3 years ago
6 0

Answer:

12 from the bookstore

Step-by-step explanation:

3 of yours ↔ 2 from the bookstore

18 of yours ↔ 12 from the bookstore


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Vickie conducts a survey of home builders to determine the average cost of building a new home. She samples 10 home builders who
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The reasons that the sample is representative:
The builders were chosen at random
The population included only builders who build in Vicki's town

Vickie wanted to determine the cost of building a house in her home, so the fact that the builders were from her town makes the sample more representative. Moreover, the random choosing of the builders helps to remove any biases that may be present.
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Find the radius of a sphere with a volume of 26, 2440 cubic inches
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8.7304 x 1010

Step-by-step explanation:

I think its that >_<

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3 years ago
What is the value of x6+y2 when x equals 1 and y equals 11
Kazeer [188]

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28

Step-by-step explanation:

x equals 1

y equals 11

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6 0
3 years ago
if you roll a fair 6-sided die 9 times, what is the probability that at least 2 of the rolls come up as a 3 or a 4?
Kay [80]

Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • There are 9 rolls, hence n = 9.
  • Of the six sides, 2 are 3 or 4, hence p = \frac{2}{6} = 0.3333

The desired probability is:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{9,0}.(0.3333)^{0}.(0.6667)^{9} = 0.026

P(X = 1) = C_{9,1}.(0.3333)^{1}.(0.6667)^{8} = 0.117

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.026 + 0.117 = 0.143

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.143 = 0.857

0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For more on the binomial distribution, you can check brainly.com/question/24863377

7 0
2 years ago
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