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torisob [31]
2 years ago
13

If set A contains four distinct numbers and set B contains seven distinct letters, how many elements are in (A U B)?​

Mathematics
1 answer:
-Dominant- [34]2 years ago
4 0

There are 11 elements are in (A U B)

<h3>How to determine the number of elements?</h3>

The given parameters are:

n(A) = 4

n(B) = 7

The number of elements in (A U B) is calculated using:

n(A U B) = n(A) +n(B) - n(A U B)

Given that the sets have distincts elements, we have:

n(A U B) = 4 + 7 - 0

Evaluate

n(A U B) = 11

Hence, there are 11 elements are in (A U B)

Read more about sets at:

brainly.com/question/2166579

#SPJ1

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<u>Step-by-step explanation:</u>

The given equation is f(x)=x^{3} +3x^{2} -25x-75 .

Add 0 at the end of the equation.

x^{3} +3x^{2} -25x-75 = 0.

Let us group the given equation,

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Join the two group since both (x+3) is common in both groups.

(x+3)(x^{2} -25) =0.

One of the factor is (x+3).

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The other factors are (x+5) and (x-5).

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