Let's call x1: The rate per hour of the number one mechanic. X2: The rate per hour of mechanic number two. The first thing you should do is identify the system of equations that best describes the problem. In this case it is a system of 2 equations with two unknowns which when solved gives a total of x1 = 85 $ / h and x2 = 50 $ / h. Attached solution.
Answer:
When y = |x + h|, the graph is shifted (or translated) <u>to the left.</u>
When y = |x - h|, the graph is shifted (or translated) <u>to the right.</u>
Step-by-step explanation:
Part A:
The parent function of vertex graphs are y = |x|, and any transformations done to y = |x| are shown in this format (also known as vertex form): y = a|x - h| + k
(h , k) is the vertex of the graph.
So, for the first part, what y = |x + h| is saying is y = |x - (-h)|.
The -h is substituted for h, and negatives cancel out, resulting in x + h.
This translates to the left of the graph.
Part B:
For the second part, y = |x - h| looks just like the normal vertex form. In this one, we are just plugging in a positive value for h.
This translates to the right of the graph.
It is D. ,that one makes the most sense to me
Answer:
a) see the plots below
b) f(x) is exponential; g(x) is linear (see below for explanation)
c) the function values are never equal
Step-by-step explanation:
a) a graph of the two function values is attached
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b) Adjacent values of f(x) have a common ratio of 3, so f(x) is exponential (with a base of 3). Adjacent values of g(x) have a common difference of 2, so g(x) is linear (with a slope of 2).
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c) At x ≥ 1, the slope of f(x) is greater than the slope of g(x), and the value of f(x) is greater than the value of g(x), so the curves can never cross for x > 1. Similarly, for x ≤ 0, the slope of f(x) is less than the slope of g(x). Once again, f(0) is greater than g(0), so the curves can never cross.
In the region between x=0 and x=1, f(x) remains greater than g(x). The smallest difference is about 0.73, near x = 0.545, where the slopes of the two functions are equal.