Please help it is for a test. The question is in the photo.

The equation is in y=mx+b format. The y is the final amount that you will have to pay. The m in this case is the amount of money that you are paying for each individual month (which is $34.99). The x in this case is the number of months you are paying for (which is 1). And b is the starting fee that you have to pay in order to get a membership in the first place (but will not have to pay after the first month). Thus, seeing as there is 1 month's worth of payment and a starting fee tagged on, y would equal the average total cost for the first month of a gym membership.

8 0

3 years ago

HELP PLS! ;P Find n. A. 5√3 B. 5 C. 10√3/3 D. 10

Readme [11.4K]

Answer:

B

Step-by-step explanation:

tan(30)=n/(5*sqrt(3))

=> n=5

4 0

3 years ago

Find the two intersection points

bogdanovich [222]

Answer:

Our two intersection points are:

$\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)$

Step-by-step explanation:

We want to find where the two graphs given by the equations:

$\displaystyle (x+1)^2+(y+2)^2 = 16\text{ and } 3x+4y=1$

Intersect.

When they intersect, their x- and y-values are equivalent. So, we can solve one equation for y and substitute it into the other and solve for x.

Since the linear equation is easier to solve, solve it for y:

$\displaystyle y = -\frac{3}{4} x + \frac{1}{4}$

Substitute this into the first equation:

$\displaystyle (x+1)^2 + \left(\left(-\frac{3}{4}x + \frac{1}{4}\right) +2\right)^2 = 16$

Simplify:

$\displaystyle (x+1)^2 + \left(-\frac{3}{4} x + \frac{9}{4}\right)^2 = 16$

Square. We can use the perfect square trinomial pattern:

$\displaystyle \underbrace{(x^2 + 2x+1)}_{(a+b)^2=a^2+2ab+b^2} + \underbrace{\left(\frac{9}{16}x^2-\frac{27}{8}x+\frac{81}{16}\right)}_{(a+b)^2=a^2+2ab+b^2} = 16$