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2 years ago

How many moles of C are in a sample of C5H12 that also contains 22.5g of H?

Chemistry

1 answer:

pishuonlain [190]2 years ago

8 0

The number of moles of C present in C₅H₁₂ that contains 22.5 g of H is 9.375 moles

<h3>How to determine the mass of C₅H₁₂ that contains 22.5 g of H</h3>

1 mole of C₅H₁₂ = (12×5) + (1×12) = 72 g

Mass of H in 1 mole of C₅H₁₂ = 12 × 1 = 12 g

Thus,

12 g of H is present in 72 g of C₅H₁₂

Therefore,

22.5 g of H will be present in = (22.5 × 72) / 12 = 135 g of C₅H₁₂

<h3>How to determine the mole of C present in 135 g of C₅H₁₂</h3>

72 g of C₅H₁₂ contains 5 moles of C

Therefore,

135 g of C₅H₁₂ will contain = (135 × 5) / 72 = 9.375 moles of C

Thus, 9.375 moles of C is present in C₅H₁₂ that contains 22.5 g of H

Learn more about mole:

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Which of the following gases would have the greatest kinetic energy at 300 K?

tekilochka [14]

Answer:

D. All of them would have the same kinetic energy

Explanation:

The expression for the kinetic energy of the gas is:-

$K.E.=\frac{3}{2}\times K\times T$

k is Boltzmann's constant = $1.38\times 10^{-23}\ J/K$

T is the temperature

<u>Since, kinetic energy depends only on the temperature. Thus, at same temperature, at 300 K, all the gases which are $N_2,\ NH_3\ and\ Ar$ will posses same value of kinetic energy.</u>

4 0

3 years ago

What is the partial pressure (in atm) of CO₂ at 468.2 K in a 25.0 L fuel combustion vessel if it contains 60.0 grams CO₂, 82.1 g

NeTakaya

Answer:

2.09 atm

Explanation:

Step 1: Given and required data

Mass of CO₂ (m): 60.0 g

Volume of the vessel (V): 25.0 L

Temperature (T): 468.2 K

We won't need the data of water and uncombusted fuel, since the partial pressures are independent of each other.

Step 2: Calculate the number of moles (n) corresponding to 60.0 g of CO₂

The molar mass of CO₂ is 44.01 g/mol.

60.0 g × 1 mol/44.01 g = 1.36 mol

Step 3: Calculate the partial pressure of CO₂

We will use the ideal gas equation.

P × V = n × R × T

P = n × R × T/ V

P = 1.36 mol × (0.0821 atm.L/mol.K) × 468.2 K/ 25.0 L = 2.09 atm

5 0

3 years ago

how many litres of 0.500M HCL(aq) are needed to react completely with 0.100 mol of Pb(NO3)2, forming a precipitate of PbCl2(s)..

katrin2010 [14]

The volume that is needed to react completely with 0.100 mol of lead nitrate is 0.400 L. It is because 2 moles of HCl are required for every mole of lead nitrate.
2 x 0.100 mole Pb(NO₃) = 0.200 mole HCl
0.200 mol HCl = L x 0.500 M

8 0

3 years ago

Read 2 more answers

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple _______. Then, plot ln(K

Aloiza [94]

Answer:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:

$\Delta G=-RTln(Ksp)\\\\\Delta G=\Delta H-T\Delta S$

Thus, by combining them, we obtain:

$-RTln(Ksp)=\Delta H-T\Delta S\\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{T\Delta S}{RT} \\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{\Delta S}{R}$

Which is related to the general line equation:

$y=mx+b$

Whereas:

$y=ln(Ksp)\\\\m=-\frac{\Delta H}{R} \\\\x=\frac{1}{T} \\\\b=\frac{\Delta S}{R}$

It means that we answer to the blanks as follows:

Regards!

8 0

3 years ago

What is the reaction?

FromTheMoon [43]

Answer:

A chemical reaction is a process in which one or more substances, also called reactants, are converted to one or more different substances, known as products. ... A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products.

Explanation:

Hopefully this is what you needed

7 0

3 years ago