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Free_Kalibri [48]
2 years ago
15

The weights of packs of chewing gum for a certain brand have a mean of 47.1 grams and a standard deviation 2.4

Mathematics
1 answer:
Verdich [7]2 years ago
4 0

A Z-score helps us to understand how far is the data from the mean. The correct option is B.

<h3>What is Z-score?</h3>

A Z-score helps us to understand how far is the data from the mean. It is a measure of how many times the data is above or below the mean. It is given by the formula,

Z = \dfrac{X- \mu}{\sigma}

Where Z is the Z-score,

X is the data point,

μ is the mean and σ is the standard variable.

The weight of a randomly selected pack of gum has a z-score of 3.11. Therefore, The weight of this pack of gum is heavier than the mean weight by 3.11 standard deviations.

Hence, the correct option is B.

Learn more about Z-score:

brainly.com/question/13299273

#SPJ1

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timurjin [86]
Its easier to ask somebody face-to-face dude
4 0
3 years ago
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Viefleur [7K]

Answer:

1. -75 ft

5/8 X  -120=    

5/8= 0.625

0.625*-120 = -75

2. 5

(-2/3) * (2.5) * (-3)

(2.5) * (-3) is -7.5

-7.5*(-2/3)

=5

3 0
3 years ago
How to evaluate question number 4
ANTONII [103]

There are 2 ways that spring to mind.

One is to use the definition of the derivative at a point:

f'(c)=\displaystyle\lim_{x\to c}\frac{f(x)-f(c)}{x-c}

In this case, c=0 and f(x)=\sqrt{5-x}. Then

f'(x)=-\dfrac1{2\sqrt{5-x}}\implies f'(0)=\displaystyle\lim_{x\to0}\frac{\sqrt{5-x}-\sqrt5}x=-\dfrac1{2\sqrt5}

- - -

If you don't know about derivative yet (I would think you do, considering this is for a midterm in AP Calc, but I digress), the other way is to rely on algebraic manipulation. Multiply the numerator and denominator by the conjugate of the numerator to get

\dfrac{\sqrt{5-x}-\sqrt5}x\cdot\dfrac{\sqrt{5-x}+\sqrt5}{\sqrt{5-x}+\sqrt5}=\dfrac{\left(\sqrt{5-x}\right)^2-\left(\sqrt5\right)^2}{x\left(\sqrt{5-x}+\sqrt5\right)}=-\dfrac x{x\left(\sqrt{5-x}+\sqrt5\right)}=-\dfrac1{\sqrt{5-x}+\sqrt5}

This is continuous at x=0, so the limit is the value of the expression at x=0:

\displaystyle\lim_{x\to0}\frac{\sqrt{5-x}-\sqrt5}x=-\lim_{x\to0}\frac1{\sqrt{5-x}+\sqrt5}=-\frac1{2\sqrt5}

5 0
3 years ago
If y varies inversely as x and y=7 when x=−4, find y when x=2.
olga2289 [7]

Answer:

Explanation:

The statement is expressed as

y

∝

1

x

inverse means

1

variable

To convert to an equation introduce k, the constant of variation.

y

=

k

×

1

x

⇒

y

=

k

x

To find k use the given condition that y = 8 when x = 4

8

=

k

4

⇒

k

=

4

×

8

=

32

⇒

equation is

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

∣

∣

2

2

y

=

32

x

2

2

∣

∣

∣

−−−−−−−−−−−−

x

=

16

→

y

=

32

16

⇒

y

=

2

when

x

=

16

5 0
3 years ago
Given ƒ(x) = 14x + 42, find x when ƒ(x) = 35. A) − 12 Eliminate B) −1 C) 1 D) 3
balandron [24]

Step-by-step explanation:

f(x)=14x+42

f(x)=35

Given the information above, we can simply set up an equation so we can find the value of x.

14x + 42 = 35

Subtract 42 on both sides.

14x=-7

Divide 14 on both sides.

x=-\frac{1}{2}

So, the value of x is equal to -1/2 when f(x) is 35.

6 0
3 years ago
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