The weights of packs of chewing gum for a certain brand have a mean of 47.1 grams and a standard deviation 2.4
1 answer:
A Z-score helps us to understand how far is the data from the mean. The correct option is B.
<h3>What is Z-score?</h3>A Z-score helps us to understand how far is the data from the mean. It is a measure of how many times the data is above or below the mean. It is given by the formula,
Where Z is the Z-score,
X is the data point,
μ is the mean and σ is the standard variable.
The weight of a randomly selected pack of gum has a z-score of 3.11. Therefore, The weight of this pack of gum is heavier than the mean weight by 3.11 standard deviations.
Hence, the correct option is B.
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There are 2 ways that spring to mind.
One is to use the definition of the derivative at a point:
In this case, and
. Then
- - -
If you don't know about derivative yet (I would think you do, considering this is for a midterm in AP Calc, but I digress), the other way is to rely on algebraic manipulation. Multiply the numerator and denominator by the conjugate of the numerator to get
This is continuous at , so the limit is the value of the expression at
:
Step-by-step explanation:
Given the information above, we can simply set up an equation so we can find the value of x.
Subtract 42 on both sides.
Divide 14 on both sides.
So, the value of x is equal to -1/2 when f(x) is 35.