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spayn [35]
2 years ago
12

Type the correct answer in each box. Spell all words correctly. Two triangles are graphed in an x y plane. The vertices are as f

ollows: first: A (negative 6, 2), B (negative 2, 6), and C (negative 4, 2); second: A prime (negative 6, negative 2), B (negative 2, negative 6), and C (negative 4, negative 2). A sequence of transformations maps ∆ABC onto ∆A″B″C″. The type of transformation that maps ∆ABC onto ∆A′B′C′ is a . When ∆A′B′C′ is reflected across the line x = -2 to form ∆A″B″C″, vertex of ∆A″B″C″ will have the same coordinates as B′.
Mathematics
1 answer:
Rus_ich [418]2 years ago
6 0

The transformation that mapped ∆ABC onto ∆A′B′C′ is a reflection over the x-axis. The coordinate of B'' would be same as that of B'.

<h3>How to solve transformation problems? </h3>

We are given the coordinates as;

∆ABC; A(-6, 2), B(-2, 6), C(-4, 2).

∆A′B′C; A'(-6, - 2), B (-2, -6), C (-4, -2).

A) Now, we are told that ∆ABC was transformed to

∆A′B′C. From the given coordinates, we see that only the y coordinate sign changed after the transformation. Thus, the transformation that mapped ∆ABC onto ∆A′B′C′ is a reflection over the x-axis.

B) Now, ∆A′B′C′ is reflected across the line x = -2 to form ∆A″B″C″. Since the line x = -2 is vertical and the coordinate of B' in ∆A′B′C′ has an x - coordinate of -2, then it means the coordinate of B'' would be same as that of B'

Read more about transformations at; brainly.com/question/4289712

#SPJ1

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