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Julli [10]
3 years ago
5

If you guys can't see it , it says Triangle JKL was translated 12 units vertically and then reflected over the y-axis to create

triangle J'K'L'
​

Mathematics
1 answer:
anyanavicka [17]3 years ago
3 0

Answer:

6

Step-by-step explanation:

-Under point reflections, figures sizes and shapes remains unchanged.

-The dimensions of JL=L\prime J\prime=8:

#We therefore equate to solve for x:

JL=L\prime J\prime\\\\8=2X-4\\\\2X=12\\\\X=6

Hence, the measure of x is 6.

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What is the value of x?
Alexus [3.1K]

Answer:

x = 22.5

Step-by-step explanation:

\frac{BH}{DH}  =  \frac{HM}{HT}  \\  \frac{6}{15 + 6}  =  \frac{9}{9 + x}  \\  \frac{6}{21}  =  \frac{9}{9 + x}  \\ 6(9 + x) = 9 \times 21 \\ 54 + 6x = 189 \\ 6x = 189 - 54 \\  6x = 135 \\ x =  \frac{135}{6}  \\ x = 22.5

5 0
3 years ago
Make this statement true
Nesterboy [21]
A is greater than -b
4 0
3 years ago
∠E and ∠F are vertical angles with m∠E=8x+8 and m∠F=2x+38<br><br> .<br><br> What is the value of x?
givi [52]
As they are vertical angles, their magnitude will be equal.
8x+8 = 2x+38
8x-2x = 38-8
6x = 30
x = 5

So, Your Final Answer would be 5

Hope this helps!
3 0
3 years ago
Read 2 more answers
Imani spent half of her weekly allowance playing mini-golf. To earn more money, her parents let her wash the car for $4. What is
joja [24]

Answer:

$16

Step-by-step explanation:

This method is probbaly working backwards. I'm not sure.

12 - 4 = 8 (How much she was left with if she didn't wash the car for 4 dollars)

8 x 2 = 16 (They mentioned she spent half of her weekly allowance)

6 0
3 years ago
Select the correct answer. Which point lies on a circle with a radius of 5 units and center at P(6, 1)? A. Q(1, 11) B. R(2, 4) C
jasenka [17]

Answer:

T(9,-2)

Step-by-step explanation:

The circle has radius 5 units and center P(6,1).

The equation of this circle is

(x-6)^2+(y-1)^2=5^2

(x-6)^2+(y-1)^2=25

If Q(1,11) lies on this circle, then it must satisfy its equation.

(1-6)^2+(11-1)^2=25

(-5)^2+(10)^2=25

25+100=25, this statement is false.

If R(2,4) lies on this circle, then it must satisfy its equation.

(2-6)^2+(4-1)^2=25

(-4)^2+(3)^2=25

16+9=25, this statement is false.

If S(4,-4) lies on this circle, then it must satisfy its equation.

(4-6)^2+(-4-1)^2=25

(-2)^2+(-5)^2=25

4+25=25, this statement is false.

If T(9,-2) lies on this circle, then it must satisfy its equation.

(9-6)^2+(-2-1)^2=25

(4)^2+(-3)^2=25

16+9=25, this statement is TRUE.

The correct answer is D

6 0
3 years ago
Read 2 more answers
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