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3 years ago

How does the entropy change in the reaction 2C3H6(g) + 902(g) → 6CO2(g) +

Chemistry

1 answer:

Sever21 [200]3 years ago

5 0

Taking into account the definition of entropy, the entropy increases (option B).

<h3>What is Entropy</h3>

Entropy can be interpreted as a measure of the random distribution of a system. In other words, the entropy S is a state function that measures the degree of molecular disorder of systems.

In this way, the change in entropy shows the change in molecular order that occurs in a chemical reaction. If the increase in entropy is positive, the products have a higher molecular disorder (higher entropy) than the reactants. On the other hand, when the increase is negative, the products are more ordered.

So, the entropy increases in the reaction if the total number of product molecules are greater than the total number of reactant molecules.

<h3>Entropy change in this case</h3>

In this case, there are 12 moles of gaseous product, and 11 moles of gaseous reactant in the equation. This is, there are more moles in the products than in the reactants.

Therefore, the entropy increases (option B).

Learn more about entropy:

brainly.com/question/22861773

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PLZZ HELPP WILL MARK BRAINLIEST

Debora [2.8K]

<h2>Balance Chemical Equation</h2>

1. N2 + 3 H2 = 2 NH3

2. 2 KCIO3 = 2 KCI + 3 O2

3. 2 NaCI + F2 = 2 CI + 2 NaF

4. 2 H2 + O2 = 2 H2O

5. Pb(OH)2 + 2 HCl = 2 H2O + PbCl2

6. 2 AlBr3 + 3 K2SO4 = 6 KBr + Al2(SO4)3

7. CH4 + 2 O2 = CO2 + 2 H2O

8. C3H8 + 5 O2 = 3 CO2 + 4 H2O

9. 2 C8H18 + 25 O2 = 16 CO2 + 18 H2O

10. FeCl3 + 3 NaOH = Fe(OH)3 + 3 NaCl

11. 4 P + 5 O2 = 2 P2O5

12. 2 Na + 2 H2O = 2 NaOH + H2

13. 2 Ag2O = 4 Ag + O2

14. S8 + 12 O2 = 8 SO3

15. 6 CO2 + 6 H2O = C6H12O6 + 6 O2

16. 2 K + MgBr2 = 2 KBr + Mg

17. 2 HCl + CaCO3 = CaCl2 + H2O + CO2

18. HNO3 + NaHCO3 = NaNO3 + H2O + CO2 - already balanced

19. 2 H2O + O2 = 2 H2O2

20. 2 NaNO3 + H2SO4 = Na2SO4 + 2 HNO3

8 0

3 years ago

22 g de um gás estão contidos em um recipiente de volume igual a 17,5 L, a uma temperatura de 77ºC e

Aleksandr-060686 [28]

Answer:

Option D.

Explanation:

Let's apply the Ideal Gases law to solve the problem.

P . V = n . R . T

First of all we convert the temperature value from °C to K

77°C + 273 = 350K

and the pressure from mmHg to atm

623 mmHg . 1 atm/760 mmHg = 0.82 atm

We replace data: 0.82 atm . 17.5L = n . 0.082 L.atm/mol.K . 350K

(0.82 atm . 17.5L) / (0.082 L.atm/mol.K . 350K) = n

0.50 moles = n

These are the moles that corresponds to 22 g of the gas, so the molar mass will be → 22g / 0.50 mol = 44 g/mol

That molar mass corresponds to CO₂ → 12 g (C) + 16 g (O) . 2 = 44 g/mol

4 0

3 years ago

Explain the economic features of gandaki province

mote1985 [20]

Answer:

there are many valleys and mountain in this region

magar,gurung,brahmins are the main inhabitants of this province

there is possibility of tourism development in this province

production of apple in mountains and coffe in hilly has made this region popular .

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em>

3 0

3 years ago

Read 2 more answers

R = 0.821 ( atm Calculate the pressure in a 212 L tank containing 584 moles of Argon gas at 25℃? (Answer = 67.3 atm)

spayn [35]

Answer:

67.3 atm

Explanation:

We'll begin by converting 25 ℃ to Kelvin temperature. This can be obtained as follow:

T(K) = T(℃) + 273

T(℃) = 25 ℃

T(K) = 25 + 273

T(K) = 298 K

Finally, we shall determine the pressure. This can be obtained by using the ideal gas equation as illustrated below:

Gas constant (R) = 0.821 atm.L/Kmol

Volume (V) = 212 L

Number of mole (n) = 584 moles

Temperature (T) = 298 K

Pressure (P) =?

PV = nRT

P × 212 = 584 × 0.0821 × 298

P × 212 = 14288.0272

Divide both side by 212

P = 14288.0272 / 212

P = 67.3 atm

Thus, the pressure is 67.3 atm

3 0

3 years ago

One piece of copper jewelry at 101°C has twice the mass of another piece, which is at 38.0°C. Both pieces are placed inside a ca

nydimaria [60]

Answer:

80.0°C will be the final temperature inside the calorimeter.

Explanation:

Heat lost by the pace of jewelry will be equal to heat gained by the another piece of the jewelry

$-Q_1=Q_2$

Mass of piece-1= $m_1=2m$

Specific heat capacity of copper= $c$ = 0.387 J/g.K

Initial temperature of the iron = $T_1=101^oC$

Final temperature = $T_2$ =T

$Q_1=m_1c_1\times (T-T_1)$

Mass of piece-2= $m_2=m$

Specific heat capacity of copper = $c$ = 0.387 J/g.K

Initial temperature of the water = $T_3=38.0^oC$

Final temperature of water = $T_2$ =T

$Q_2=m_2c_2\times (T-T_3)$

$-Q_1=Q_2$ (conservation of energy)

$-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)$

On substituting all values:

$-(2mc\times (T-101^oC))=mc\times (T-38.0^oC)$

$T= 80.0^oC$

80.0°C will be the final temperature inside the calorimeter.

8 0

4 years ago