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Feliz [49]
3 years ago
10

PLZZ HELPP WILL MARK BRAINLIEST

Chemistry
1 answer:
Debora [2.8K]3 years ago
8 0
<h2>Balance Chemical Equation</h2>

1. N2 + 3 H2 = 2 NH3

2. 2 KCIO3 = 2 KCI + 3 O2

3. 2 NaCI + F2 = 2 CI + 2 NaF

4. 2 H2 + O2 = 2 H2O

5. Pb(OH)2 + 2 HCl = 2 H2O + PbCl2

6. 2 AlBr3 + 3 K2SO4 = 6 KBr + Al2(SO4)3

7. CH4 + 2 O2 = CO2 + 2 H2O

8. C3H8 + 5 O2 = 3 CO2 + 4 H2O

9. 2 C8H18 + 25 O2 = 16 CO2 + 18 H2O

10. FeCl3 + 3 NaOH = Fe(OH)3 + 3 NaCl

11. 4 P + 5 O2 = 2 P2O5

12. 2 Na + 2 H2O = 2 NaOH + H2

13. 2 Ag2O = 4 Ag + O2

14. S8 + 12 O2 = 8 SO3

15. 6 CO2 + 6 H2O = C6H12O6 + 6 O2

16. 2 K + MgBr2 = 2 KBr + Mg

17. 2 HCl + CaCO3 = CaCl2 + H2O + CO2

18. HNO3 + NaHCO3 = NaNO3 + H2O + CO2 - already balanced

19. 2 H2O + O2 = 2 H2O2

20. 2 NaNO3 + H2SO4 = Na2SO4 + 2 HNO3

You might be interested in
What is the volume of 7.50x10^24 molecules of NH3 at STP
Bas_tet [7]

Answer:

V NH3 = 304.334 L

Explanation:

  • 1 mol ≡ 6.02 E23 molecules

⇒ moles NH3 = (7.50 E24 molecules)×(mol/6.022 E23 molecules)

⇒ mole NH3 = 12.454 mol

assuming ideal gas:

  • PV = RTn

STP:

∴ T = 25°C ≅ 298 K

∴ P = 1 atm

⇒ V NH3 = RTn/P

⇒ V NH3 = ((0.082 atm.L/K.mol)×(298 K)×(12.454 mol))/(1 atm)

⇒ V NH3 = 304.334 L

4 0
4 years ago
Which one is equivalent to 28% by mass? 0/1 point O 28 g solute perg of solvent 28 g solute per g of solution 28 g solute per 10
astra-53 [7]

Answer:

28 g solute per 100 g of solution

Explanation:

28% mass means that in all your solution you have 28% of your solute, you could use grames/grames, ml/ml or whatever you want to. So if you are working with a 100 grams solution, 28 grams of that solution must be solute if you want a 28% mass. So, the correct answer is 28 g solute per 100 g of solution.

3 0
4 years ago
13.<br> Which contains the same number of molecules as 22.4 liters of N2 at STP?
Oksanka [162]

Answer:

Delete my comment if your gay

Explanation:

7 0
3 years ago
Cyanogen is a gas which contains 46.2% C and 53.8% N by mass. At a temperature of 25°C and a pressure of 750 mm Hg, 1.50 g of cy
sergiy2304 [10]

Answer:

Molecular formula of cyanogen is C₂N₂

Explanation:

We apply the ideal gases law to find out the mole of cyanogen

P . V =  n. R. T

Firstly let's convert the pressure in atm, for R

750 mmHg = 0.986 atm

25°C + 273 = 298K

0.986 atm . 0.714L = n . 0.082 L.atm/mol.K .298K

(0.986 atm . 0.714L) / (0.082 L.atm/mol.K .298K) = n

0.0288 mol = n

Molar mass of cyanogen = mass / mol

1.50 g /0.0288 mol = 52.02 g/m

Let's apply the percent, to know the quantity of atoms

100 g of compound contain 46.2 g of C and 53.8 g of N

52.02 g of compound contain:

(52.02 . 46.2) / 100 = 24 g  → 2 atoms of C

(52.02 . 53.8) / 100 = .28 g  →  2 atoms of N

3 0
3 years ago
Convert 1000DM to km
irinina [24]

Answer:0.1

Explanation:

8 0
3 years ago
Read 2 more answers
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