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Feliz [49]
3 years ago
10

PLZZ HELPP WILL MARK BRAINLIEST

Chemistry
1 answer:
Debora [2.8K]3 years ago
8 0
<h2>Balance Chemical Equation</h2>

1. N2 + 3 H2 = 2 NH3

2. 2 KCIO3 = 2 KCI + 3 O2

3. 2 NaCI + F2 = 2 CI + 2 NaF

4. 2 H2 + O2 = 2 H2O

5. Pb(OH)2 + 2 HCl = 2 H2O + PbCl2

6. 2 AlBr3 + 3 K2SO4 = 6 KBr + Al2(SO4)3

7. CH4 + 2 O2 = CO2 + 2 H2O

8. C3H8 + 5 O2 = 3 CO2 + 4 H2O

9. 2 C8H18 + 25 O2 = 16 CO2 + 18 H2O

10. FeCl3 + 3 NaOH = Fe(OH)3 + 3 NaCl

11. 4 P + 5 O2 = 2 P2O5

12. 2 Na + 2 H2O = 2 NaOH + H2

13. 2 Ag2O = 4 Ag + O2

14. S8 + 12 O2 = 8 SO3

15. 6 CO2 + 6 H2O = C6H12O6 + 6 O2

16. 2 K + MgBr2 = 2 KBr + Mg

17. 2 HCl + CaCO3 = CaCl2 + H2O + CO2

18. HNO3 + NaHCO3 = NaNO3 + H2O + CO2 - already balanced

19. 2 H2O + O2 = 2 H2O2

20. 2 NaNO3 + H2SO4 = Na2SO4 + 2 HNO3

You might be interested in
You have to prepare some 2 M solutions, with 10 g of solute in each. What volume of solution will you prepare, for each solute b
alexdok [17]

Answer:

             0.045 L  or 45 mL

Explanation:

Moles = Mass/M.Mass

Moles = 10 g / 109.94 g/mol

Moles = 0.09 moles

Also,

Molarity = Moles / Vol in L

Or,

Vol in L = Moles / Molarity

Vol in L = 0.09 mol / 2 mol/L

Vol in L = 0.045 L

8 0
2 years ago
A tablet of Pain Be Gone Aspirin, which had a mass of 1.213 g, was pulverized and 1.159 g were dissolved in 10.0 mL of ethyl alc
Elan Coil [88]

Answer:

a. Moles of NaOH  = 0.001643 moles

b. 0.296 g

c. 0.3098 g

d. Not acceptable

Explanation:

a.

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For NaOH :

Molarity = 0.1052 M

Volume = 15.62 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 15.62×10⁻³ L

Thus, moles of NaOH :

Moles=0.1052 \times {15.62\times 10^{-3}}\ moles

Moles of NaOH  = 0.001643 moles

b.

The reaction of NaOH with the acetylsalicylic acid is in the ratio of 1:1.

Thus, Moles of NaOH = Moles of acetylsalicylic acid = 0.001643 moles

Molar mass of acetylsalicylic acid = 180.16 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Mass = Moles * Molar mass = 0.001643 moles * 180.16 g/mol = 0.296 g

c.

1.159 g of sample contains 0.296 g of acetylsalicylic acid

1.213 g of sample contains \frac{0.296}{1.159}\times 1.213 g of acetylsalicylic acid

Mass of acetylsalicylic acid = 0.3098 g = 309.8 mg

d. Sample contains = 309.8 mg

Manufacturer claiming = 315 mg to 335 mg

Thus , it is not acceptable.

5 0
3 years ago
A sample of gas has a mass of 0.560 g . Its volume is 125 mL at a temperature of 85 ∘C and a pressure of 757 mmHg .
-BARSIC- [3]

Answer:

132g/mole

Explanation:

using the formula PV=nRT should be used to solve for the number of moles (n).  R is a constant which is 62.3637 L mmHG/mole K.

Inorder for your units to match you will have to convert 125ml to .125L and the temperature of 85C to K . you do that by adding 273 to the 85C and get 358K.  Once you solve for n then you use that number and divide by the number of grams from the question (.560g) since molar mass is grams/moles.

4 0
3 years ago
several factors, including time, motion, temperature, and contact area, affect the_____ of dissolving.
Liula [17]
I think the missing word is rate
5 0
3 years ago
If 1,079.75 Joules of heat are added to 77.75 grams of water, by how many degrees Celsius would the water increase? Assume water
djyliett [7]

Answer:

If 1,079.75 Joules of heat are added to 77.75 grams of water, by 3.32 degrees Celsius the temperature of  water will increase

\Delta T=3.32 C^{0}

Explanation:

q = mC\Delta T

Here , q = heat added / removed from the substance

m  = mass of the substance taken

\Delta T = Change in temperature

C = specific heat capacity of the substance

In liquid state the value of C for water is :

4.18 J/gC^{0}

Given values :

q = 1079.75 J

m = 77.75 gram

Insert the value of C, m , q in the given equation

q = mC\Delta T

on transposing ,

\Delta T=\frac{q}{mC}

\Delta T=\frac{1079.75}{77.75\times 4.18}

\Delta T=3.32 C^{0}

3 0
3 years ago
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