Question

Can someone help with number 4. I will reward brainliest.

Answer 1

Let's simplify the problem down a little:

 ⇒ set 'sin(θ)' as x

    ⇒ the new equation looks like: $2x^2+5x-3=0$

Now let's solve this equation as a quadratic:

 $2x^2+5x-3=0\\(2x-1)(x+3)=0\\\\2x-1=0\\x = \frac{1}{2} \\\\x+3 = 0\\x=-3$

Now set the x value of '1/2', to sin(θ)

• it can't be -3, because trig functions can't equal a negative number

         sin(θ) = 1/2

            θ = π/6, which is between the range given

Answer: π/6

Hope that helps!

Answer 2

Answer:

theta = pi/6 and

theta = 5pi/6

Step-by-step explanation:

see image. Factor the expression. Solve for sin theta. Then use a calculator or unit circle to solve for theta. See image.