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mariarad [96]
1 year ago
13

Which of these factors should remain constant in a simulation of natural

Chemistry
1 answer:
musickatia [10]1 year ago
8 0
A is your answer The ratio of females to males
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I agree with the person on top have a beautiful day:)
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3 years ago
What is the <br> formula for gunpowder
mrs_skeptik [129]

Here is the chemical equation for gun powder, in it’s simple form:

<span>2 KNO3 + S + 3 C → K2S + N2 + 3 CO2.</span>

This is the same simplified formula, only balanced:

<span>10 KNO3 + 3 S + 8 C → 2 K2CO3 + 3 K2SO4 + 6 CO2 + 5 N2.</span>

3 0
3 years ago
Explain why the first ionisation energy of krypton is greater then the first ionisation energy of bromine
MrMuchimi

Answer:

Kr has one more electron than br and so, the nuclear charge increase, which means the nuclear attraction between the nucleus and outer most electron will increase and so will be harder to remove the electron from Kr than Br, so Kr has higher 1st ionisation.

Mark me brainliest!

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3 0
3 years ago
Explain how our body systems work together to get oxygen into and around our body. Answer must be three sentences long
sashaice [31]

Inhales. Oxygen - good for the body - gives it to the Circulatory System to be transported throughout the body through the blood. Digestive System gets nutrients from food and hands it over to the blood and Circulatory System then carries those nutrients where they need to go.

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8 0
2 years ago
Read 2 more answers
How many molecules of co2 form when 2.00 g of c2h5oh are produced?
Ronch [10]
The reaction involved in this problem is called the combustion reaction where a hydrocarbon reacts with oxygen to product carbon dioxide and water. The reaction of C2H5OH would be as follows:

C2H5OH + 3O2 = 2CO2 + 3H2O

To determine the number of molecules of CO2 that is formed, we need to determine the number of moles produced from the initial amount of C2H5OH and the relation from the reaction. Then we multiply avogadros number which is equal to 6.022x10^23 molecules per mole. 

2.00 g C2H5OH ( 1 mol C2H5OH / 46.08 g C2H5OH ) ( 2 mol CO2 / 1 mol C2H5OH ) = 0.0868 mol CO2
0.0868 mol CO2 ( 6.022x10^23 molecules / mol ) = 5.23x10^22 molecules CO2
4 0
3 years ago
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