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mariarad [96]
1 year ago
13

Which of these factors should remain constant in a simulation of natural

Chemistry
1 answer:
musickatia [10]1 year ago
8 0
A is your answer The ratio of females to males
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PLEASE ANSWER ASAP!!!!!!! 50 points if the answer is correct!
Ad libitum [116K]

5

 mL acetic acid

95

mL water

Explanation:

Since

5

%

of the vinegar, by volume, is acetic acid, and we have

100

mL of vinegar, we have

5

mL of vinegar.

Similarly, we have

100

%

−

5

%

=

95

%

being water, so we have

95

mL of water.

8 0
2 years ago
3. Give an example of how carbon is transferred frem being in a living to a non-living<br> organism.
slavikrds [6]

Answer:

Carbon moves from living things to the atmosphere. Each time you exhale, you are releasing carbon dioxide gas (CO2) into the atmosphere. Animals and plants need to get rid of carbon dioxide gas through a process called respiration. Carbon moves from fossil fuels to the atmosphere when fuels are burned.

4 0
3 years ago
You use 4.98 g of Na2SO4, how many grams of barium sulfate are produced?<br><br> Na2+Ba(NO3)2= ?
Kaylis [27]

Answer:

Mass of barium sulfate = 8.17 g

Explanation:

Given data:

Mass of sodium sulfate = 4.98 g

Mass of barium sulfate produced = ?

Solution:

Na₂SO₄ + Ba(NO₃)₂    →   BaSO₄ + 2NaNO₃

Moles of sodium sulfate:

Number of moles = mass/molar mass

Number of moles =4.98 g / 142.04 g/mol

Number of moles = 0.035 mol

Now we will compare the moles pf sodium sulfate and with barium sulfate.

                            Na₂SO₄               :            BaSO₄

                                1                       :              1

                              0.035                :          0.035

Mass of barium sulfate:

Mass = number of moles × molar mass

Mass =   0.035 mol ×233.4 g/mol

Mass = 8.17 g

6 0
3 years ago
Is malachite A mineral, a rock or neuter
dybincka [34]

a malachite is a mineral

5 0
3 years ago
Convert 5.28 x 1019 molecules of C6H1206 to grams.
nlexa [21]

Answer:

m=0.0158g

Explanation:

Hello there!

In this case, it is possible to comprehend these mass-particles problems by means of the concept of mole, molar mass and the Avogadro's number because one mole of any substance has 6.022x10²³ particles and have a mass equal to the molar mass.

In such a way, for C₆H₁₂O₆, whose molar mass is about 180.16 g/mol, the referred mass would be:

m=5.28x10^{19}molecules*\frac{1mol}{6.022x10^{23}molecules}*\frac{180.16g}{1mol}\\\\m=0.0158g

Best regards!

5 0
3 years ago
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