What particle(s) of an atom would NOT found in the nucleus?
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Considering the definition of molar mass, the moles of gas used are 10.625 moles.
<h3>Definition of molar mass</h3>The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.
<h3>Amount of moles used</h3>Natural gas has a molar mass of 16.0 g/mole.
You started out the day with a tank containing 200.0 g of natural gas. So, you can apply the following rule of three: If by definition of molar mass 16 grams are contained in 1 mole, 200 grams are contained in how many moles?
<u><em>amount of moles at the beginning= 12.5 moles</em></u>
At the end of the day, your tank contains 30.0 g of natural gas. So, you can apply the following rule of three: If by definition of molar mass 16 grams are contained in 1 mole, 30 grams are contained in how many moles?
<u><em>amount of moles at the end= 1.875 moles</em></u>
The number of moles used will be the difference between the number of moles used initially and the contents at the end of the day.
moles used= amount of moles at the beginning - amount of moles at the end
moles used= 12.5 moles - 1.875 moles
<u><em>moles used= 10.625 moles</em></u>
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Finally, the moles of gas used are 10.625 moles.
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Answer:
1.09 M
Explanation:
Let's define the equation that will be used to calculate the final concentration of the resultant calcium nitrate solution. In order to calculate it, we need to find the total number of moles of calcium nitrate and divide by the total volume of the resultant solution:
This equation firstly helps us find the number of moles of calcium nitrate. Multiplying molarity by volume will yield the moles. Adding the moles from the first component to the second component will provide us with the total number of moles of calcium nitrate:
Now, the total volume of this solution can be found by adding the volume values of each component:
Finally, dividing the moles found by the total volume will yield the final molarity: