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Tju [1.3M]
2 years ago
14

Two trains leave two different stations 300 km apart; the first starts at noon and the second at 12 15 h. Travelling on parallel

tracks, they meet each other at 15 00 h. Each train travels at a constant speed, the one leaving at 12 15 h moves at 15 km/h faster than the other. What are their speeds?​
Mathematics
1 answer:
alexgriva [62]2 years ago
8 0

Answer:

See below

Step-by-step explanation:

From noon to 1500  is three hours

  train A    then travels  <u> 3x</u>   where x = speed in km/hr

  train B   only travels for 2.45 hours and covers

                  <u>   2.45 ( x + 15)  </u>        where x + 15 is its speed in km/hr

       these two values sum to the 300 km distance

3x     +     2.45 ( x + 15) = 300

3x + 2.45 x  + 36.75 = 300

x = 48.3 km/hr       x+15= 63.3 km / hr

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2 years ago
Find sin X, sin Z, cos X, and cos Z. Write each answer as a simplified fraction.
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Answer:

Find the answers below

Step-by-step explanation:

Using m<X as the reference angle

Opposite YZ = 7

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Hypotenuse XZ = √149

Using the SOH CAH TOA identity

sinX = opp/hyp

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cos X =10/√149

Using m<Z as reference angle;

Opposite XY = 10

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Using the SOH CAH TOA identity

sinZ = opp/hyp

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2 years ago
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Arrange the steps from start to finish to factor this expression using the grouping method x^2-5x-24 drag the tiles to the corre
rosijanka [135]

Answer:

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Step-by-step explanation:

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Consider the factors of - 24 which sum to give the coefficient of the x- term (- 5)

The factors are - 8 and + 3 , since

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2 years ago
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sashaice [31]

Answer:

the angle between their paths is <em>100.8°</em>

Step-by-step explanation:

From the given information, you can construct a triangle, just like the one in the figure.

We will use the <em>Cosine Rule</em> which is:

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