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Tju [1.3M]
2 years ago
14

Two trains leave two different stations 300 km apart; the first starts at noon and the second at 12 15 h. Travelling on parallel

tracks, they meet each other at 15 00 h. Each train travels at a constant speed, the one leaving at 12 15 h moves at 15 km/h faster than the other. What are their speeds?​
Mathematics
1 answer:
alexgriva [62]2 years ago
8 0

Answer:

See below

Step-by-step explanation:

From noon to 1500  is three hours

  train A    then travels  <u> 3x</u>   where x = speed in km/hr

  train B   only travels for 2.45 hours and covers

                  <u>   2.45 ( x + 15)  </u>        where x + 15 is its speed in km/hr

       these two values sum to the 300 km distance

3x     +     2.45 ( x + 15) = 300

3x + 2.45 x  + 36.75 = 300

x = 48.3 km/hr       x+15= 63.3 km / hr

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Answer:

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Step-by-step explanation:

There are two ways that you can solve this. You can solve it with the help of technology or you can solve it traditionally. I will show how to do it in both ways so you can pick which way you want to solve it.

<em>Traditional Method:</em>

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Look at the variables and numbers in both equations. One of them has to be the same value but have to have opposite signs. The 2y in both equations are the same value but have different signs. That's what we want. We can add everything in the equation now. (5x + 6x), (-2y + 2y), and (12 + 32).

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Good! We figured out y. Now we know the solution! The solution is (4,4).

<em>Technology Method:</em>

Grab a graphing calculator. Enter the equations. You will see two lines. Look at where they intersect. The point where they intersect is the solution. That line is (4,4). You could also do this on a piece of paper by graphing the equations.

I hope this helps! Let me know if you need any more help or if I got anything wrong.

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