Two trains leave two different stations 300 km apart; the first starts at noon and the second at 12 15 h. Travelling on parallel
1 answer:
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Answer:
r = 2
r = -1
Step-by-step explanation:
So first, we need to get this is order of: ax^2 + bx + c
3r^2 - 6 - 3r
3^2 - 3r - 6
the formula is: -b ± √b^2 -4ac/2a
"ax^2 + bx + c" = "3^2 - 3r - 6"
a = 3
b = -3
c = -6
-b ± √b^2 -4ac/2a
-(-3) ± √(-3)^2 -4(3)(-6)/2(3)
3 ± √9 + (-12)(-6)/6
3 ± √9 + (72)/6
3 ± √9 + 72/6
3 ± √81/6
3 ± 9/6
3 - 9/6
-6/6
-1 = r
3 + 9/6
12/6
2 = r
Formula down below --
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