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3 years ago

Ax + by = c find Y show steps

Mathematics

1 answer:

OverLord2011 [107]3 years ago

7 0

Ax + by = c

Ax + by (- Ax) = c (-Ax)

by = c - Ax

by/b = (c - Ax)/b

y = (c - Ax)/b

hope this helps :D

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-8<2x-4<4 solve the inequality

il63 [147K]

Answer:

Step-by-step explanation:

The inequality will be split into two

It is know that, if a<b<c

Then a<b and b<c

-8<2x-4<4

Apply that to this

Then,

-8<2x-4. Equation 1

Also,

2x-4<4 equation 2

Solving equation 1

-8<2x-4

Add 4 to both side of the equation

-8+4<2x-4+4

-4<2x

Divide both sides by 2

-4/2<2x/2

-2<x

Note, if a is less than b, then, b is greater than a, e.g. 4 is less than 10, this implies 10 is greater than 4

Therefore,

-2<x

Then, x greater than -2

Equation 2

2x-4<4

Add 4 to both side of the inequalities

2x-4+4<4+4

2x<8

Divide both side by 2

Then,

2x/2<8/2

x<4

Therefore x is between -2 and +4.

Check attachment for graphical solution

7 0

3 years ago

What is the solution to the system of equations? Use any method you like, but be sure to show all work.

jeka57 [31]

These are known as simultaneous equations,,
2x + y= -3 take this as 1st equation
x-2y=-4 take this as 2 nd equation

therefore x - 2y= -2 should be multiplied by 2 inorder to cut off 2x and 2x from the first and second equations.

by multiplying we get 2x - 4y = -4

therefore 3rd equation should be substracted from 1st equation...

now, 2x -4y - 2x -y = -4-(-3)

therefore, -2x and +2x is cut.

as a result -5y= -1

therefore y = 1 /5

then let us find x

2x + y = -3
::: 2x + 1/5= -3
therefore 2x= -3-1/5

finally, x= -16/5÷2
then x= 8/5

3 0

3 years ago

Convert r = 8cos θ to rectangular form.

skelet666 [1.2K]

Answer:

Step-by-step explanation:

To convert from polar to rectangular form

• x = rcosΘ , y = rsinΘ

• r = $\sqrt{x^2+y^2}$ ⇒ r² = x² + y²

Given

r = 8cosΘ

r = 8 × $\frac{x}{r}$ ( multiply both sides by r )

r² = 8x, hence

x² + y² = 8x ⇒ D

8 0

4 years ago

What is the 5th term in the following sequence:<br> 2, 5, 11, 23...<br> Helpppp

lbvjy [14]

Answer:The first few Thabit numbers are: 2, 5, 11, 23, 47, 95, 191, 383, 767, 1535, 3071, 6143, 12287, 24575, 49151, 98303, 196607, 393215, 786431, 1572863, ...

...

Thabit number.

Named after Thābit ibn Qurra

First terms 2, 5, 11, 23, 47, 191, 383, 6143, 786431

Largest known term 3×211,895,718 − 1

OEIS index A007505

Step-by-step explanation:

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BARSIC [14]

Answer:

Step-by-step explanation:

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2 years ago