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jeyben [28]
3 years ago
6

Which of the following is the slope of a line that is perpendicular to y= -1/3x+4

Mathematics
1 answer:
garri49 [273]3 years ago
4 0

Opposite conjugate.
(-1/3) is (3/1)
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How many different phone numbers are possible in the area code 503, if the first number cannot start with a 0 or 1
ElenaW [278]

Answer:

8 X 10^(9)

Step-by-step explanation:

Originally we have 10 digit phone numbers excluding the area code.

For each face value we have these in store: 0,1,2,3,4,5,6,7,8,9 (total 10)

But if we exclude 1 and 0 for the first digit, we are left with 8 digits.

8P1 X .......

In a phone number, digits can repeat so we can choose out of these 10 numbers freely after this.

8P1 X 10P1 X 10P1 X...

Adding the area code while assuming 10P1 is just 10...we get:

1 X 1 X 1 X 8 X 10^(9)

= 8000000000

Very interesting question, thanks for the opportunity!

7 0
3 years ago
Read 2 more answers
Find the value of x. Round to the nearest tenth.
serg [7]

Answer:

Where is the equation?

Step-by-step explanation:

8 0
3 years ago
How do you solve for x in a math question like this 5+4x=54-3x?
Bas_tet [7]

To solve for x, first you need to isolate all x terms on the same side so:

you start with 5 + 4x = 54 - 3x

subtract 5 from both sides to get 5 onto the left side

now you should have 4x = 49 - 3x

now add 3x to both sides to get 3x onto the right side

now you should have 7x = 49

now that you have your x on one side you can solve this like a regular one step equation and divide both sides by 7

this leads you to your answer of x = 7

hope this helps!

6 0
3 years ago
Read 2 more answers
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
3 years ago
Rebotar Inc.makes basketballs.Their fixed costs are $3,450.
melomori [17]

Answer:

<em>Since the profit is positive, Rebotar not only broke even, they had earnings.</em>

Step-by-step explanation:

<u>Function Modeling</u>

The costs, incomes, and profits of Rebotar Inc. can be modeled by means of the appropriate function according to known conditions of the market.

It's known their fixed costs are $3,450 and their variable costs are $12 per basketball produced and sold. Thus, the total cost of Rebotar is:

C(x) = 12x + 3,450

Where x is the number of basketballs sold.

It's also known each basketball is sold at $25, thus the revenue (income) function is:

R(x) = 25x

The profit function is the difference between the costs and revenue:

P(x) = 25x - (12x + 3,450)

Operating:

P(x) = 25x - 12x - 3,450

P(x) = 13x - 3,450

If x=300 basketballs are sold, the profits are:

P(300) = 13(300) - 3,450

P(300) = 3,900 - 3,450

P(300) = 450

Since the profit is positive, Rebotar not only broke even, they had earnings.

8 0
2 years ago
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