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Serggg [28]
2 years ago
10

Simplify. Remove all perfect squares from inside the square root. √/3065 =

Mathematics
1 answer:
REY [17]2 years ago
4 0
There are none. The factors are 1, 5, 613, and of course 3065 and none are perfect squares.
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Geometry please help!
ikadub [295]

Answer:

see explanation

Step-by-step explanation:

The sum of the interior angles of a polygon is

sum = 180° (n - 2) ← n is the number of sides

The polygon here has 8 sides, that is n = 8, thus

sum = 180° × 6 = 1080°

Sum the given angles and equate to 1080, that is

14x + 133 + 167 + 138 + 18x + 115 + 151 + 120 = 1080

32x + 824 = 1080 ( subtract 824 from both sides )

32x = 256 ( divide both sides by 32 )

x = 8

Thus the 2 unknown angles are

14x = 14 × 8 = 112°

18x = 18 × 8 = 144°

8 0
3 years ago
Define the domain:  {(2,3),(0,3),(4,2),(5,6)}
Y_Kistochka [10]
For the following relation the domain would be all of the x coordinates.
D=A. 2,0,4,5
5 0
2 years ago
Sarah used 2.5 cups of cheese in a dish that serves 5 people. How many cups of cheese is needed
Alekssandra [29.7K]

Answer:

0.5 cups or 1/2 a cup per person

Step-by-step explanation:

becasue there are 2.5 SERVED to 5 people served is a key word btw. and it would make sence for people to get less than the total

6 0
3 years ago
Read 2 more answers
Can someone please help me​
astra-53 [7]

Answer:

square 20 has 44 green squares

square 21 has 45 green squares

Step-by-step explanation:

To solve the problem, we need to observe the cases, and determine/define a rule for each case (odd number of sides, or even number of sides).

For square one, we note that the centre square is shared by two diagonals, so we saved one square from the two diagonals.

The side length is 3 for square 1, 4 for square 2, and so on.

Let

n= square number (1, 2,3...)

L = side length (3,4,5...)

G1(n) = function that gives the number of green squares for square n, n=odd

G2(n) = function that gives the number of green squares for square n, n=even

side length, L=n+2   ................(1)

G1(n) = twice the side length less one, as discussed above

G1(n) = 2L-1       now substitute L=n+2

G1(n) = 2(n+2) -1    simplify

G1(n) = 2n + 3

Check:

for n=1, square 1 has 2*1+3 = 5 green squares ... checks

for n=3, square 3 has 2*3+3 = 9... checks

for n=5, square 5 has 2*5+3 = 13 ....checks

For even squares, it is even easier, because

G2(n) = 2L = 2(n+2)

check:

for n=2, square 2 has 2(2+2) = 8 green squares........checks

for n=4, square 4 has 2(4+2) = 12 green squares........checks.

Fincally, we apply our formula to n=20 and n=21

square 20 : G2(20) = 2(n+2) = 2(20+2) = 44 green quars

square 21 : G1(21) = 2n+3 = 2(21)+3 = 45 green squares

5 0
3 years ago
Expand.<br> If necessary, combine like terms.<br> (x – 5)2 =
grin007 [14]

To expand  you must first distribute (multiply) the 2 to the numbers inside the parentheses

2(x - 5)

(2 * x) + (2 * (-5) )

2x + (-10)

2x - 10

There are no like terms, therefore (x - 5)2 expanded is 2x - 10

Hope this helped!

~ Just a girl in love with Shawn Mendes

8 0
3 years ago
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