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nikklg [1K]
2 years ago
12

An alkene X undergoes ozonolysis and gives two compounds Y and Z of molecular formula CaHO. Y and Z are functional isomers of ea

ch other i. Write the two-steps chemical equation for the conversion of X into Y and Z. [2] ii. Write the structural formula of Y and Z. Why are they called functional isomers? [3] iii. What happens when hydrogen gas in the presence of nickel catalyst is passed over X? [1] iv. What is the application of ozonolysis in the organic reaction mechanism? [1] How can you prove chemically the compound X is unsaturated? ​
Chemistry
1 answer:
lys-0071 [83]2 years ago
5 0

i. The given compound X is 2-methyl pent-2-ene. When it is reacted with ozone it forms an ozonide in the first step. In the second step the reduce to forms acetone and propanal.

ii. The structural formula of Y is CH_3-CO-CH_3 and Z is CH_3-CH_2-CHO.

iii. Alkenes, upon catalytic hydrogenation, form alkanes. This will occur in the presence of Nickel as the catalyst.

iv. The process of ozonolysis is useful in the field of pharmaceutics.

v. The test of unsaturation can be performed by passing a compound through Bromine water.

<h3>What is ozonolysis?</h3>

Ozonolysis is a reaction used in organic chemistry to determine the position of a carbon-carbon double bond in unsaturated compounds.

i. The given alkene X, that is subject to ozonolysis would be 2-methyl-2-pentene. Upon exposure to ozone, an ozonide is initially formed, after which it is broken down into 2 products - acetone and propanal, both with the molecular formula C₃H₆O.

The given compound X is 2-methyl pent-2-ene. When it is reacted with ozone it forms an ozonide in the first step. In the second step the reduce to forms acetone and propanal.

ii. The formulas of Y is CH_3-CO-CH_3 and Z is CH_3-CH_2-CHO. They are functional isomers as they have the same molecular formula but different functional groups - ketone and aldehyde.

iii. When alkenes undergo catalytic hydrogenation, they form alkanes, X will form 2 methyl petane on reaction with hydrogen gas in presence of Ni.

iv. The ozonolysis is used for the industrial-scale synthesis of pharmaceuticals.

v. The unsaturation of compound X can be proved by the bromine water test. As on reaction with it, the brown colour of bromine water becomes colourless due to the formation of dibromo alkane.

Learn more about the ozonolysis here:

brainly.com/question/14356308

#SPJ1

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Fill in the blanks:
Misha Larkins [42]

Answer:

1. smaller. 2. smaller. 3. greater

Explanation:

1. H−O−H angle is 104.45  and H−C−H angle is 109.5

2. O−S−O angle is 119 and F−B−F angle is 120

3. The F−S−F bond angle in SF₆ is 90 and F−Br−F bond angle in BrF₅ is 84.8

8 0
3 years ago
All organic compound soluble in WATEe and conduct electrically ​
Delvig [45]

No

Explanation:

Not all organic substances are soluble in water and will not conduct electricity. Only polar organic compounds are soluble in water and will conduct electricity.

  • The general rule of solubility is that like dissolves likes.
  • Polar compounds will only dissolve other polar compounds too. Water is a polar solvent.
  • Non-polar compounds will only dissolve in non-polar compounds too.
  • Since water is a polar organic compound, only polar organic compounds will dissolve in it.
  • Not all organic compounds are polar.
  • When a compound dissolves in water, it produces ions that makes it able to conduct electricity.
  • Fats and oil are insoluble in water

learn more:

Inorganic compounds brainly.com/question/5047702

#learnwithBrainly

4 0
3 years ago
What is water classified as
Montano1993 [528]
Water, or H2O, is a compound composed of the elements hydrogen (H) and oxygen (O).
3 0
3 years ago
A 0.595 g sample of a metal, M, reacts completely with sulfuric acid according to the reaction M ( s ) + H 2 SO 4 ( aq ) ⟶ MSO 4
zalisa [80]

Answer:

molar mass M(s) = 65.326 g/mol

Explanation:

  • M(s) + H2SO4(aq) → MSO4(aq) + H2(g)

∴ VH2(g) = 231 mL = 0.231 L

∴ P atm = 1.0079 bar

∴ PvH2O(25°C) = 0.03167 bar

Graham´s law:

⇒ PH2(g) = P atm - PvH2O(25°C)

⇒ PH2(g) = 1.0079 bar - 0.03167 bar = 0.97623 bar = 0.9635 atm

∴ nH2(g) = PV/RT

⇒ nH2(g) = ((0.9635 atm)(0.231 L))/((0.082 atmL/Kmol)(298 K))

⇒ nH2(g) = 9.1082 E-3 mol

⇒ n M(s) = ( 9.1082 E-3 mol H2(g) )(mol M(s)/mol H2(g))

⇒ n M(s) = 9.1082 E-3 mol

∴ molar mass M(s) [=] g/mol

⇒ molar mass M(s) =   (0.595 g) / (9.1082 E-3 mol)

⇒ molar mass M(s) = 65.326 g/mol

7 0
3 years ago
How many grams of NaHCO3 are needed to prepare 250 mL of 0.50 M<br> NaHCO3?
forsale [732]

Answer:

10.5g

Explanation:

First, let us calculate the number of mole of NaHCO3 present in the solution. This is illustrated below:

Volume = 250mL = 250/1000 = 0.25L

Molarity = 0.5M

Mole =?

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 0.5 x 0.25

Mole = 0.125 mole

Now, we shall be converting 0.125 mole of NaHCO3 to grams to obtain the desired result. This can be achieved by doing the following:

Molar Mass of NaHCO3 = 23 + 1 + 12 +(16x3) = 23 + 1 +12 +48 = 84g/mol

Number of mole of NaHCO3 = 0.125 mole

Mass of NaHCO3 =?

Mass = number of mole x molar Mass

Mass of NaHCO3 = 0.125 x 84

Mass of NaHCO3 = 10.5g

Therefore, 10.5g of NaHCO3 is needed.

6 0
2 years ago
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