The answer to the question
Answer:
Frequency = 0.005× 10¹⁷ s⁻¹
E = 0.03 × 10⁻²⁰KJ
Explanation:
Given data:
Wavelength of light = 630.0 nm (630 × 10⁻⁹ m)
Frequency of light = ?
Energy in joule = ?
Solution:
speed of light = wavelength × frequency
Frequency = speed of light / wavelength
Frequency = 3 × 10⁸ m/s / 630 × 10⁻⁹ m
Frequency = 0.005× 10¹⁷ s⁻¹
Energy:
E = h. f
E = 6.63× 10⁻³⁴ Kg. m²/s × 0.005× 10¹⁷ s⁻¹
E = 0.03 × 10⁻¹⁷ j
E = 0.03 × 10⁻¹⁷ j×1 kj /1000 j
E = 0.03 × 10⁻²⁰KJ
Answer:
The chemistry formulas are formed by the chemical reactions of chemical substances.
Explanation:
The chemical substances are introduced together to find the chemical reactions and then equations are formed. The equations them used to form the formulas for the chemical reactions that are performed. The quantity of the acid and base need to be carefully introduced when performing a titration process.
An alloy is the solid solution of a metal or non-metal dissolved in a metal.
Answer:
d)Cells 1 and 2
Explanation:
In a voltaic cell, oxidation occurs at the anode and reduction occurs at the cathode. The half cell that function as anode or cathode in a voltaic cell depends strictly on the reduction potential of the metal ion/metal system in that half cell.
Examining the reduction potentials of the various metal ion/metal systems in the three half cells;
Cu= +0.34 V
Ni= -0.25 V
Zn= -0.76 V
Fe(Fe2+)= -0.44 V
Hence only Zn2+ has a more negative reduction potential than Fe2+. The more negative the reduction potential, the greater the tendency of the system to function as the anode. Thus iron half cell will function as anode in cells 1&2 as explained in the argument above.
