Answer:
To the right
Explanation:
CH₃OH(g) + heat <=> CO(g) + 2H₂(g)
According to Le Chatelier's principle, a decrease in pressure will shift the equilibrium position to the side where there is a higher volume.
From the balanced equation above,
Volume of reactant = 1
Volume of product = 1 + 2 = 3
From the above, we can see that the volume of the gasous product is higher than the volume of the gasous reactant.
Therefore, a decrease in the pressure of the system will shift the equilibrium position to the right.
Answer:
First Part: branched chain, cycloalkane, straight chain
Second Part: straight chain, branched chain, cycloalkane.
Explanation:
Edg 2021
Assuming that the nests are bird's nests and the data is a data gathered by the biologists about those nests.
A hurricane would cause some damage to the nests that is existent and cause a remarkably low count even during breeding season. It would also influence later birds because of population weakening due to the hurricane.
Answer:
Yes, Pb3(PO4)2.
Explanation:
Hello there!
In this case, according to the given balanced chemical reaction, it is possible to use the attached solubility series, it is possible to see that NaNO3 is soluble for the Na^+ and NO3^- ions intercept but insoluble for the Pb^3+ and PO4^2- when intercepting these two. In such a way, we infer that such reaction forms a precipitate of Pb3(PO4)2, lead (II) phosphate.
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Answer:
Mass = 42.8g
Explanation:
4 NH 3 ( g ) + 5 O 2 ( g ) ⟶ 4 NO ( g ) + 6 H 2 O ( g )
Observe that every 4 mole of ammonia requires 5 moles of oxygen to obtain 4 moles of Nitrogen oxide and 6 moles of water.
Step 1: Determine the balanced chemical equation for the chemical reaction.
The balanced chemical equation is already given.
Step 2: Convert all given information into moles (through the use of molar mass as a conversion factor).
Ammonia = 63.4g × 1mol / 17.031 g = 3.7226mol
Oxygen = 63.4g × 1mol / 32g = 1.9813mol
Step 3: Calculate the mole ratio from the given information. Compare the calculated ratio to the actual ratio.
If all of the 1.9831 moles of oxygen were to be used up, there would need to be 1.9831 × 4 / 5 or 1.5865 moles of Ammonia. We have 3.72226 moles of ammonia - Far excess. Because there is an excess of Ammonia, the Oxygen amount is used to calculate the amount of the products in the reaction.
Step 4: Use the amount of limiting reactant to calculate the amount of H2O produced.
5 moles of O2 = 6 moles of H2O
1.9831 moles = x
x = (1.9831 * 6 ) / 5
x = 2.37972 moles
Mass of H2O = Molar mass * Molar mass
Mass = 2.7972 * 18
Mass = 42.8g
