Answer:
in the acceleration process the quantity α and w must increase
the deceleration process the alpha quantity must constant a direction opposite to the angular velocity
Explanation:
Acceleration and angular velocity are related to linear
v = w xr
a = αx r
The bold letters indicate vectors and the cross is a vector product, therefore if
we can see that the relationship between linear and angular variables is direct
therefore in the acceleration process the quantity α and w must increase as well as their linear counterparts
in the deceleration process the alpha quantity must constant as the linear acceleration and must have a direction opposite to the angular velocity
Answer:

Explanation:
From the diagram affixed below completes the question
Now from the diagram; We need to resolve the force at point A into (3) components ; i.e x.y. & z directions which are equivalent to 
So;
= positive x axis
Negative y axis
= positive z axis
Then;

From equation (1); Let's make
the subject of the formula ; then :

Substituting the value for
into equation (2) ; we have:

The force the box is exerting on Manuel is the weight of the box, downward:

and this force is perfectly balanced by the constraint reaction applied by Manuel's hand, pushing upward.
Because the car has more mass than the wheel spinning backwards
If mass doubled and the force remained constant then the acceleration would also double
Hopes this helps