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3 years ago

2. An element is a mixture of two isotopes. One isotope has an atomic mass of 34.969 amu and an

Physics

2 answers:

yKpoI14uk [10]3 years ago

7 0

Answer:

0.3567

Explanation:

aliina [53]3 years ago

4 0

Answer: The average atomic mass of an element is 35.67 amu and the unknown element will be chlorine.

Explanation:

Mass of isotope 1 = 34.969 amu

% abundance of isotope 1 = 64.88% = $\frac{64.88}{100}=0.6488$

Mass of isotope 2 = 36.966 amu

% abundance of isotope 2 = (100-64.88)% = $\frac{100-64.88}{100}=0.3512$

Formula used for average atomic mass of an element :

$\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})$

$A=\sum[34.969\times 0.6488)+(36.966 \times 0.3512]]$

$A=35.67amu$

Therefore, the average atomic mass of an element is 35.67 amu and the unknown element will be chlorine.

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2 years ago

At 900.0 K, the equilibrium constant (Kp) for the following reaction is 0.345. 2SO2(g)+O2(g)→2SO3(g) At equilibrium, the partial

elena55 [62]

Answer : The partial pressure of $SO_3$ is, 67.009 atm

Solution : Given,

Partial pressure of $SO_2$ at equilibrium = 30.6 atm

Partial pressure of $O_2$ at equilibrium = 13.9 atm

Equilibrium constant = $K_p=0.345$

The given balanced equilibrium reaction is,

$2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)$

The expression of $K_p$ will be,

$K_p=\frac{(p_{SO_3})^2}{(p_{SO_2})^2\times (p_{O_2})}$

Now put all the values of partial pressure, we get

$0.345=\frac{(p_{SO_3})^2}{(30.6)^2\times (13.9)}$

$p_{SO_3}=67.009atm$

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2 years ago

(Mass vs. Weight) HELP PLZ!!

Lina20 [59]

$\huge \boxed { \sf{Answers}}$

c. The weight of an object on the moon will be the same as its weight on Earth. It is false because the weight of an on the moon will be 1/6 th times its weight on Earth.
d. The weight of an object is its mass multiplied by the force of gravity. The statement is false because the formula of weight is mass × acceleration due to gravity, not force of gravity.
e. The mass and weight of an object are the same thing. The statement is false because mass means a body of matter. While weight of an object is its mass multiplied by the force of gravity.
f. The mass of an object is the force of gravity acting upon an object. It is false because it will be the weight of the object not mass.
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2 years ago

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3 years ago

A small sphere with mass m is attached to a massless rod of length L that is pivoted at the top, forming a simple pendulum. The

USPshnik [31]

Answer:

a) see attached, a = g sin θ

c) v = √(2gL (1-cos θ))

Explanation:

In the attached we can see the forces on the sphere, which are the attention of the bar that is perpendicular to the movement and the weight of the sphere that is vertical at all times. To solve this problem, a reference system is created with one axis parallel to the bar and the other perpendicular to the rod, the weight of decomposing in this reference system and the linear acceleration is given by

Wₓ = m a

W sin θ = m a

a = g sin θ

b) The diagram is the same, the only thing that changes is the angle that is less

θ' = 9/2 θ

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The easiest way to find linear speed is to use conservation of energy

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Lowest point

Emf = K = ½ m v²

Em₀ = Emf

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v = √(2gL (1-cos θ))

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3 years ago