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klemol [59]
3 years ago
14

2. An element is a mixture of two isotopes. One isotope has an atomic mass of 34.969 amu and an

Physics
2 answers:
yKpoI14uk [10]3 years ago
7 0

Answer:

0.3567

Explanation:

aliina [53]3 years ago
4 0

Answer: The average atomic mass of an element is 35.67 amu and the unknown element will be chlorine.

Explanation:

Mass of isotope 1 = 34.969 amu

% abundance of isotope 1 = 64.88% = \frac{64.88}{100}=0.6488

Mass of isotope 2 =  36.966 amu

% abundance of isotope 2 = (100-64.88)% = \frac{100-64.88}{100}=0.3512

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[34.969\times 0.6488)+(36.966 \times 0.3512]]

A=35.67amu

Therefore, the average atomic mass of an element is 35.67 amu and the unknown element will be chlorine.

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A woman dropped a dime in a wishing well , she heard it 30 sec later ..Find velocity on impact while moving at 9.8 m/s 2
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Answer:

The velocity at impact is 222.2 m/s

Explanation:

The given information are;

The time at which the woman heard the sound of the coin after dropping it into the wishing well = 30 seconds

The average speed of sound in air = 344 m/s

The time in which the dime travel = t₁

The time in which the sound travel = t₂

1/2 × 9.8 × t₁² = 344 × t₂

t₁ + t₂ = 30

4.9·t₁² = 344 × (30 - t₁)

4.9·t₁² + 344·t₁ - 10320 = 0

Which gives -344±

t_1 = \dfrac{-344\pm \sqrt{344^{2}-4\times 4.9 \times 10320}}{2\times 4.9}

t₁  = 22.676 seconds or -92.9 seconds

Therefore the correct natural time is t₁  = 22.676 seconds

The velocity at impact, v = g×t₁ = 9.8 × 22.676  = 222.2 m/s

The velocity at impact= 222.2 m/s.

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