Se necesita 105 j de trabajo para mover 2,7 c de carga de la placa negativa a la placa positiva de un condensador de placa paralela. Qué diferencia de tensión existe entre las placas
There
are five layers of the atmosphere and these are; troposphere, stratosphere,
mesosphere, thermosphere and exosphere. The first layer, troposphere, is where
we are able to do most of our activities. This is where we can see the formation
of clouds, the production of rain, hail, snow and other weather phenomenon.
Also, this layer is where the greatest amount of air pressure because most of
the molecules of air are in this area. Like us, air has also mass and the
pressure is brought down by the earth’s gravity causing an increase in weight
exerted on you as you descend lower into the atmosphere. So, as you enter into
the other layers of atmosphere above the troposphere, the air pressure starts
to decrease. <span>Below the atmosphere
is the hydrosphere. This is where all liquid forms are located. And since the
seawater has a greater mass than air, it has the greatest pressure. </span>
A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs.
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Answer:
a) No, Two vectors with different magnitudes can never add up to zero.
b) Yes, Three or more vectors with different magnitudes can add up to zero.
Explanation:
a) No, Two vectors with different magnitudes can never add up to zero.
Given vector A and B
A = (x1,y1,z1) and B = (x2,y2,z2)
For A + B = 0
This conditions must be satisfied.
x1 + x2 = 0
y1 + y2 = 0
z1 + z2 = 0
Therefore, for those conditions to be meet the magnitude of A must be equal to that of B.
b) Yes, Three or more vectors with different magnitudes can add up to zero.
For example, three forces acting at equilibrium like supporting the weight of a person with two different ropes.
W = T1 + T2
Where;
W = Weight
T1 = tension of wire 1
T2 = tension of wire 2
Hi there!
a.
We know that:
Begin by determining the forces in the vertical direction:
W = weight of traffic light
T₁sinθ = vertical component of T₁
T₂sinθ = vertical component of T₂
b.
The ropes provide a horizontal force:
T₁cosθ = Horizontal component of T1
T₂cosθ = Horizontal component of T2
Thus:
0 = T₁cosθ - T₂cosθ
T₁cosθ = T₂cosθ
T₁ = T₂
c.
Since the angles for both ropes are the same, we can say that:
T₁ = T₂
Sum the forces:
ΣFy = T₁sinθ + T₁sinθ - W = 0
2T₁sinθ = W
d.
Now, we can begin by solving for the tensions:
2T₁sinθ = W
