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serg [7]
4 years ago
14

The unit for measuring electric power is the A. ampere. B. volt. C. ohm. D. watt.

Physics
1 answer:
Drupady [299]4 years ago
6 0
The correct answer is D: Watt. This unit was named after James Watt, and is used to express the equivalent of one joule per second in energy. In experiments and on the packaging for electrical products such as light-bulbs, the measurement will usually be written in its abbreviated format: W.
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Three short square wood blocks measuring 3.5 per side support a machine weighing 29500 lbs. What is the compressive stress in th
Ilya [14]

Answer:

D. 803 lbs

Explanation:

In order to find the compressive stress on all three blocks we first need to find the normal surface area of each:

Surface Area of 1 Block = 3.5 x 3.5

Surface Area of 1 Block = 12.25

Surface Area of all 3 Blocks = A = 3 x 12.25

Area = 36.75

Now, the stress is given by the following formula:

Stress = Force/Area

Stress = 29500 lbs/36.75

Stress = 802.72 lbs

Hence, the correct option will be:

<u>D. 803 lbs</u>

4 0
4 years ago
A 70.0 kg ice hockey goalie, originally at rest, has a 0.110 kg hockey puck slapped at him at a velocity of 31.5 m/s. Suppose th
NISA [10]

Answer

given,

mass of the goalie(m₁) = 70 kg

mass of the puck (m₂)= 0.11 kg

velocity of the puck = 31.5 m/s

elastic collision

v_1=\dfrac{m_2-m_1}{m_1+m_2}v_1+\dfrac{2m_2}{m_1+m_2}v_2

v_{pf}=\dfrac{0.11-70}{0.11+70}31.5+\dfrac{2m_2}{m_1+m_2}\times (0)

v_{pf}=-31.4\ m/s

v'_2 = \dfrac{2m_1v_1}{m_1+m_2}-\dfrac{(m_2-m_1)v_2}{m_2+m_1}

v_{gf} = \dfrac{2\times 0.11\times 31.5}{0.11+70}-\dfrac{(0.11-70)\times 0}{m_1+m_2}

v_{gf} = \dfrac{2\times 0.11\times 31.5}{0.11+70}

v_{gf} = 0.0988\ m/s

4 0
3 years ago
Three students derive the following equations in which x refers to distance traveled, v the speed, a the acceleration (m/s^2), a
Lynna [10]

Answer:

B) and C)

Explanation:

Dimensional check involves using the units of the fundamental quantities, like mass to verify the accuracy of a formula or model.

For this case, the quantities required are Length and Time. Their units are Metre (m) and Seconds (s) respectively.

Since x refers to Distance, v refers to velocity, a refers to acceleration and t refers to time,

A) x = vt² + 2at

=> m = (m/s * s²) + (m/s² * s)

m = ms + m/s

The units are unbalanced, hence, it is not dimensionally correct.

B) x = v₀t + 2at²

=> m = (m/s * s) + (m/s² * s²)

m = m + m

The units are balanced, hence, it is dimensionally correct.

C) x = v₀t + ¹/₂at²

=> m = (m/s * s) + (m/s² * s²)

m = m + m

The units are balanced, hence, it is dimensionally correct.

3 0
3 years ago
What is the frequency of a wave that passes a given point 22 times in 2.0 seconds? A. 44 Hz B. 11 Hz C. 0.091 s D. 24 s
FrozenT [24]
The answer is B. 11 Hz. 

Frequency is always measured in Hertz (Hz), so it can't be C. or D. anyway, but the way to work this out is to do 22 ÷ 2 to work out 11 Hz, because you work out frequency as per second. Also, the formula is f (frequency) = <span>V (velocity) / λ (wavelength). </span>
8 0
4 years ago
Read 2 more answers
The length of nylon rope from which a mountain climber is suspended has a force constant of 1.40 × 10^4 N/m .
docker41 [41]

Answer:

w = 12.5 rad/s   and A = 50 10⁻² m

Explanation:

Let's treat this problem as a case of oscillatory movement

a) The angular velocity is given by

       w² = k / m

       w = √ 1.4 10⁴/90.0

       w = 12.5 rad / s

b) It is climber falls by two meters, its mechanical energy at the highest point is

       Em = U = mgh

       Em = 90 9.8 2

       Em = 1764 J

The energy of the harmonic oscillator can be calculated

       E = ½ k A²

Where A is the amplitude of the movement. This is going to be the stretch for the mechanical energy of the fall

      A² = 2E / k

      A = √(2 1764 /1.40 10⁴)

      A = 50 10⁻² m

c) To realize this part, you must know how the force constant changes with the length, in the case of two springs joined along its axis

   1 /k equivalent = 1 / k1 + 1 / k2

4 0
3 years ago
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