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2 years ago

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Chemistry

1 answer:

ICE Princess25 [194]2 years ago

7 0

Answer:

yes so for example one

Explanation:

yeah so

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How many grams of sodium chloride are required to make a 1.0 L solution with a concentration of 3.5 M?

satela [25.4K]

3.5 M has 3.5 moles per litre
so we have one litre, so we need 3.5 moles
moles = mass/molarmass
3.5 * 23 = 80.5

5 0

3 years ago

Read 2 more answers

An experimental spacecraft consumes a special fuel at a rate of 372 L/min. The density of the fuel is 0.730 g/mL and the standar

Karolina [17]

Explanation:

First, we will calculate fuel consumption is as follows.

$372 L/min \times 1000 ml/L \times 0.730 g/ml \times \frac{1}{60} min/s$

= 4526 g/s

Now, we will calculate the power as follows.

Power = Fuel consumption rate × -enthalpy of combustion

= $4526 g/s \times -26.5 kJ/g$

= $1.19 \times 10^{5}$ kW

Thus, we can conclude that maximum power (in units of kilowatts) that can be produced by this spacecraft is $1.19 \times 10^{5}$ kW.

5 0

3 years ago

The daily production of carbon dioxide from an 780.0 mw coal-fired power plant is estimated to be 3.3480 x 104 tons (not metric)

valkas [14]

The production of $CO_{2}$ is $3.3480\times 10^{4} tons/day$ . Converting mass into kg,

1 ton=907.185 kg, thus,

$3.3480\times 10^{4} tons=3.037\times 10^{7} kg$

Thus, production of $CO_{2}$ will be $3.037\times 10^{7} kg/ day$ .

The specific volume of $CO_{2}$ is $0.0120 m^{3}/kg$ .

Volume of $CO_{2}$ produced per day can be calculated as:

$V=Specific volume\times mass$

Putting the values,

$V=0.0120 m^{3}/kg\times 3.037\times 10^{7} kg=364440 m^{3}/day$

Thus, volume of $CO_{2}$ produced per year will be:

$V=\frac{365 days}{1 year}(364440 m^{3}/day)=1.33\times 10^{8}m^{3}/year$

Thus, in 4 year volume of $CO_{2}$ produced will be:

$V=1.33\times 10^{8}m^{3}/year\times 4 years=5.32\times 10^{8}m^{3}$

8 0

3 years ago

What is the molar mass of cholesterol if 0.00105 mol weigh 0.406 g?

Rudiy27

Answer:

387 g/mol

Explanation:

The molar mass is a ratio comparing a substance's mass and molar value. The specific ratio looks like this:

Molar Mass (g/mol) = mass (g) / moles

You can plug the given values into the ratio to find the molar mass.

Molar Mass = mass / moles

Molar Mass = 0.406 g / 0.00105 mol

Molar Mass = 387 g/mol

8 0

2 years ago

At stp 5.6 liters of ch4 which element contains the same number of molecules?

Alinara [238K]

Answer:

5.6 L of hydrogen

Explanation:

when 5.6 liter is added of hydrogen, the value equallify and becomes right

4 0

3 years ago