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1 year ago

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Which reactant is unlikely to produce the indicated product upon strong heating?

1 answer:

Ilya [14]1 year ago

8 0

2-Methyl-4-oxo-pentanoic acid is unlikely to produce 2-Methyl-3-butanone upon strong heating.

Upon heating, the β ketoacid becomes unstable and decarboxylates, leading to the formation of the methyl ketone.

A carboxylic acid is an organic acid that contains a carboxyl group (C(=O)OH) attached to an R-group. The general formula of a carboxylic acid is R−COOH or R−CO2H, with R referring to the alkyl, alkenyl, aryl, or other group.

Carboxylic acids occur widely. Important examples include the amino acids and fatty acids. Deprotonation of a carboxylic acid gives a carboxylate anion.

Full question :

Q. Which reactant is unlikely to produce the indicated product upon strong heating?

A) 2,2-Dimethylpropanedioic acid 2-methylpropanoic acid
B) 2-Ethylpropanedioic acid Butanoic acid
C) 2-Methyl-3-oxo-pentanoic acid 3-Pentanone
D) 2-Methyl-4-oxo-pentanoic acid 2-Methyl-3-butanone
E) 4-Methyl-3-oxo-heptanoic acid 3-Methyl-2-hexanone

Hence, option (D) is correct.

Learn more about carboxylic acid here : brainly.com/question/26855500

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The energy range expected is 6.6 × 10^-19 J < E < 7.33 × 10^-19 J

The energy of the photon is given by;

E = hc/λ

E = energy of the photon

h = Plank's constant

c = speed of light

λ = wavelength of light

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E = ?

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