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ddd [48]
2 years ago
15

Which reactant is unlikely to produce the indicated product upon strong heating?

Chemistry
1 answer:
Ilya [14]2 years ago
8 0

2-Methyl-4-oxo-pentanoic acid  is unlikely to produce 2-Methyl-3-butanone upon strong heating.

Upon heating, the β ketoacid becomes unstable and decarboxylates, leading to the formation of the methyl ketone.

A carboxylic acid is an organic acid that contains a carboxyl group (C(=O)OH) attached to an R-group. The general formula of a carboxylic acid is R−COOH or R−CO2H, with R referring to the alkyl, alkenyl, aryl, or other group.

Carboxylic acids occur widely. Important examples include the amino acids and fatty acids. Deprotonation of a carboxylic acid gives a carboxylate anion.

Full question :

Q.  Which reactant is unlikely to produce the indicated product upon strong heating?

  • A) 2,2-Dimethylpropanedioic acid 2-methylpropanoic acid
  • B) 2-Ethylpropanedioic acid Butanoic acid
  • C) 2-Methyl-3-oxo-pentanoic acid 3-Pentanone
  • D) 2-Methyl-4-oxo-pentanoic acid 2-Methyl-3-butanone
  • E) 4-Methyl-3-oxo-heptanoic acid 3-Methyl-2-hexanone

Hence, option (D) is correct.

Learn more about carboxylic acid here : brainly.com/question/26855500

#SPJ4

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Answer:

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Explanation:

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This relationship is due to the assumption that there are no attractive forces between the gases.

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You know:

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