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ch4aika [34]
2 years ago
7

Explain why there might be a change in the density of a forged product as compared to that of the cast blank.

Chemistry
1 answer:
kkurt [141]2 years ago
4 0

Answer:

Forged parts are often tougher than cast parts. This can be determined by performing tensile tests on various areas on the parts. Additionally, the microstructures of forged and cast parts can be used to determine if a part was forged or cast. The microstructure of a cast part will have a more uniform grain structure.

Explanation:

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A sample of a pure substance with a density of 3 g/mL is separated into two pieces. One piece has a mass of 50 g and the other p
pshichka [43]

Answer:

8.3ml

Explanation:

to get volume u have to divide 25g over the density, i rounded to the nearest tenth, if you don't want to then write out the full number with all the decimals

4 0
2 years ago
Determine which of these properties would distinguish these two substances: (a) boiling point; (b) combustion analysis results;
Nutka1998 [239]

Answer:

(a) boiling point

(d) density at a given temperature and pressure.

Explanation:

Isomers are compounds that have the same molecular formula but different structural formulas. They differ in chemical and physical properties depending on the type of isomerism displayed by the compounds.

The compounds stated here are structural or constitutional isomers hence they possess different boiling points and densities at a given temperature and pressure owing to structural differences in the molecules.

Since they have the same molecular formula, they must yield the same result during combustion analysis and they must have the same molecular weight.

3 0
3 years ago
Simon has collected three samples from the coral reef where he observes marine life. He must determine whether each one is a pur
-Dominant- [34]

Answer:

SAMPLE A - pure substance.

SAMPLE B - homogeneous mixture.

SAMPLE C - heterogeneous mixture.

Explanation:

3 0
3 years ago
Balance this equation and pick the answer with the coefficients that belong there.
geniusboy [140]

Answer:

2,3,6,1

2,3,6,1

Explanation:

The unbalanced reaction expression is given as:

  AlBr₃    +    K₂SO₄  →    KBr  + Al₂(SO₄)₃

We need to balanced this reaction equation. Our approach is a mathematical method where we assign variable a,b,c and d as the coefficients.

 aAlBr₃    +    bK₂SO₄  →    cKBr  + dAl₂(SO₄)₃

Conserving Al;  a  = 2d

                   Br:  3a  = c

                   K:   2b = c

                   S:   b  = 3d

                   O:  4b  = 12d

Let a  = 1, c = 3, d  = \frac{1}{2}  b  = \frac{3}{2}  

 Multiply through by 2 to give;

     a  = 2, b = 3, c = 6 and d  = 1

 2AlBr₃    +    3K₂SO₄  →    6KBr  + Al₂(SO₄)₃

6 0
2 years ago
Which equation will you use to calculate the volume of a 5.00 liter sample of air at 50°C when it is warmed to 100°C at constant
Alexandra [31]
I believe it's a proportion of volume over temperature = volume and temperature. cross multiply and divide and see what u get. if it looks right go fro it if not try something else. I hope this helps!
6 0
3 years ago
Read 2 more answers
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