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2 years ago

7

Explain why there might be a change in the density of a forged product as compared to that of the cast blank.

1 answer:

kkurt [141]2 years ago

4 0

Answer:

Forged parts are often tougher than cast parts. This can be determined by performing tensile tests on various areas on the parts. Additionally, the microstructures of forged and cast parts can be used to determine if a part was forged or cast. The microstructure of a cast part will have a more uniform grain structure.

Explanation:

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Enzyme, fat, sugar. Classify them into the group of organic compounds to which they belong to

Vilka [71]

Enzymes are proteins and speed up chemical reactions, i.e. are catalysts.
Fats are lipids and store energy.
Sugars are carbohydrates and also store energy.
hope this helps :)

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3 years ago

If every oxygen ion (combined with an aluminum ion) has a charge of –2, what must the charge of each aluminum ion be? How can yo

Andrews [41]

Each aluminium ion should have a charge of +2, because the sum of oxidation numbers must be zero.

The uncharged aluminium atom must lose two electrons to become an ion with +2 charge.

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3 years ago

Use what you know about the orbits of Earth and the moon to sort the phrases into the correct Category.

Kobotan [32]

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Astrophysics.

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3 years ago

What is the Molarity of a solution of HNO3 if it contains 12.6 moles in a<br> 0.75 L solution? *

Korolek [52]

Answer:

M = 16.8 M

Explanation:

<u>Data:</u> HNO3

moles = 12.6 moles

solution volume = 0.75 L

Molarity is represented by the letter M and is defined as the amount of solute expressed in moles per liter of solution.

$M=\frac{moles}{solution volume}$

The data is replaced in the given equation:

$M=\frac{12.6 mol}{0.75L}=16.8\frac{mol}{L}$

7 0

3 years ago

Read 2 more answers

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In

adell [148]

Answer:

The net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is 523.2 kJ.

Explanation:

Step 1:

$CaC_2(s) + 2H_2O(g)\rightarrow C_2H_2(g) + Ca(OH)_2(s),\Delta H_1=414.0 kJ$ ...[1]

Step 2 :

$6C_2H_2(g) + 3CO_2(g) + 4H_2O(g)\rightarrow 5CH_2CHCO_2H(g) \Delta H_2=132.0kJ$ ..[2]

Adding 6 × [1] and [2]:

$6CaC_2(s) + 12H_2O(g)\rightarrow 6C_2H_2(g) + 6Ca(OH)_2(s)$

$6C_2H_2(g)+3CO_2(g)+16H_2O(g)\rightarrow 5CH_2CHCO_2H(g)$

we get :

$6CaC_2(s) + 8H_2O(g)+3CO_2(g)\rightarrow 5CH_2CHCO_2H(g)+ 6Ca(OH)_2(s),\Delta H'=?$

$\Delta H'=6\times \Delta H_1+\Delta H_2$

$\Delta H'=6\times 414.0 kJ+132.0kJ$

$\Delta H'=2,626 kJ$

Energy released on formation of 5 moles of acrylic acid = 2,626 kJ

Energy released on formation of 1 mole of acrylic acid:

$\frac{ 2,626 kJ}{5 } = 523.2 kJ$

7 0

4 years ago