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goblinko [34]
3 years ago
6

Current Question:

Chemistry
1 answer:
IRISSAK [1]3 years ago
7 0

Answer:

0.2g

Explanation:

All radiodecay follows the 1st order decay equation

A = A₀e^-kt

A => Activity at time (t)

A₀ => Initial Activity at time = 0

k => decay constant for isotope

T => time in units that match the decay constant

Half-Life Equation => kt(½) = 0.693 => k = 0.693/34 min = 0.0204min¹

A = A₀e^-kt  = (26g)e^-(0.0204/min)(238min) = (26g)(0.0078) = 0.203g ~ 0.2g (1 sig fig).

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      <em><u>calculation</u></em>

  • <em><u>  </u></em>find the mole  of  each element

        that is  moles for Li,Cl,O and that of H2O

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        that  is  for  Li= 0.624/0.623=  1

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<h3>Therefore the formula=LiClO4.3H2O</h3><h3 />
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