Question

Carol has some dimes and quarters. If she has 19 coins worth a total of $3.10, how many of each type of coin does she have?

Answer 1

Answer:

Step-by-step explanation:

Equations

Let the dimes be x

Let the quarters be y

x + y = 19                     (1)                   Multiply this equation by 0.1

0.1x + 0.25y = 3.10     (2)

0.1x + 0.1 y =    1.90     (3)                   Subtract 3 from 2

          0.15y  =  1.20                            Divide by 0.15

          0.15y/0.15 = 1.20/0.15

                 y = 8

x + y = 19

x + 8 = 19                                               Subtract 8 from both sides

x+8-8  = 19-8                                          Combine

x = 11

Answer

Carol has 8 quarters

She has 11 dimes

                     

Answer 2

She has 8 quarters 11 dimes