Answer:

Explanation:

simplify the following

subtract 1 from both sides

simplify the following

multiply both sides by 1/3

simplify the following

Divide to get a low form of a fraction.
13 divide by 13 = 1
78/13 = 6
1/6 would therefore, be the lowest form
Answer:
y = 3x - 4
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (0, - 4) and (x₂, y₂ ) = (2, 2) ← 2 points on the line
m =
=
= 3
Note the line crosses the y- axis at (0, - 4) ⇒ c = - 4
y = 3x - 4 ← equation of line
Answer:
Minimum value of function
is 63 occurs at point (3,6).
Step-by-step explanation:
To minimize :

Subject to constraints:

Eq (1) is in blue in figure attached and region satisfying (1) is on left of blue line
Eq (2) is in green in figure attached and region satisfying (2) is below the green line
Considering
, corresponding coordinates point to draw line are (0,9) and (9,0).
Eq (3) makes line in orange in figure attached and region satisfying (3) is above the orange line
Feasible region is in triangle ABC with common points A(0,9), B(3,9) and C(3,6)
Now calculate the value of function to be minimized at each of these points.

at A(0,9)

at B(3,9)

at C(3,6)

Minimum value of function
is 63 occurs at point C (3,6).
The product of a negative integer and a positive integer is a negative integer. The product of two positive integers or two negative integers is a positive integer. That means if you multiply two OF the same sign numbers, the product is always positive. SAME.