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2 years ago

In the reaction shown,

Chemistry

1 answer:

exis [7]2 years ago

8 0

Answer:

Ni (s) is oxidized because it loses electrons. This makes it the reducing agent.

CuCl₂ (aq) is reduced because it gains electrons. This makes it the oxidizing agent.

Explanation:

In the reaction:

Ni(s) + CuCl₂(aq) → Cu(s) + NiCl₂(aq)

Ni (s) is oxidized because it loses electrons. This makes it the reducing agent.

------------> Ni (s) has an oxidation number of 0. All lone atoms (that are not ions) have a 0 oxidation number.

-------------> In NiCl₂ (aq), chlorine must have an oxidation number of -1, and because there are two chorine atoms, they contribute a total -2 charge. To make the overall charge neutral, nickel must have an oxidation number of +2 to balance the charges.

--------------> Because nickel goes from an oxidation number of 0 to +2, this indicates that it lost electrons and was reduced.

CuCl₂ (aq) is reduced because it gains electrons. This makes it the oxidizing agent.

-------------> In CuCl₂ (aq), chlorine must have an oxidation number of -1, and because there are two chorine atoms, they contribute a total -2 charge. To make the overall charge neutral, copper must have an oxidation number of +2 to balance the charges.

------------> Cu (s) has an oxidation number of 0. All lone atoms (that are not ions) have a 0 oxidation number.

--------------> Because copper goes from an oxidation number of +2 to 0, this indicates that it gained electrons and was oxidized.

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sertanlavr [38]

According to the statement

2.12 x 10^4 lbs pounds of CaCO₃ are needed to neutralize this acid

<h3>What is neutralization?</h3>

A chemical reaction in which an acid and a base react quantitatively with each other is known as neutralization or neutralization. In a water reaction, neutralization ensures that there is no excess of hydrogen or hydroxide ions in the solution.

<h3>According to the given information:</h3>

The equation of the neutralization reaction between H2SO4 and CaCO3.

CaCO3 + H2SO4 → CaSO4 + H2CO3

H2CO3 dissociate to water and carbon dioxide.

CaCO3 + H2SO4 → CaSO4 + H2O + CO2

Now solving for the mass of CaCO3 needed to neutralize the acid.

mass of CaCO3 = 9460 Kg H2SO4 × $\frac{1000 \mathrm{~g}}{1 \mathrm{~kg}} \times \frac{1 \mathrm{~mol} \mathrm{H}_2 \mathrm{SO} 4}{98.1 \mathrm{gH}_2 \mathrm{SO}_4} \times \frac{1 \mathrm{~mol} \mathrm{CaCO}\left(\mathrm{O}_3\right.}{1 \mathrm{~mol} \mathrm{H}_2 \mathrm{SO}_4}$ $\times \frac{100.1 \mathrm{~g} \mathrm{CaCO}_3}{1 \mathrm{~mol} \mathrm{CaCO}_3} \times \frac{2.205 \mathrm{lb}}{1000 \mathrm{~g}}$

= 21284.56606

mass of CaCO3 = 2.12 x 10^4 lbs

2.12 x 10^4 lbs pounds of CaCO₃ are needed to neutralize this acid.

To know more about neutralization visit:

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4 0

1 year ago

If the theoretical yield of a reaction is 0.110 g and the actual yield is 0.104 g , what is the percent yield?

Westkost [7]

Theoretical Yield is an Ideal yield with 100 % conversion of reactant to product. It is in fact a paper work.

While,

Actual Yield is the yield which is obtained experimentally. It is always less than theoretical yield because it is not possible to have 100% conversion of reactants into products. Even some amount of product is lost while handling it during the process.

Percentage Yield is Calculated as,

%age Yield = Actual Yield / Theoretical Yield × 100

Data Given:
Actual Yield = 0.104 g

Theoretical Yield = 0.110 g

Putting Values,

%age Yield = 0.104 g / 0.110 g × 100

%age Yield = 94.54 %

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2 years ago

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MaRussiya [10]

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