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natta225 [31]
4 years ago
13

Which graph shows the relationship between the temperature and volume of agas according to Charles's law?Volume vs. Temperature

of a Gasvolume vs. Temperature of a Gas160140140'E 20o A. 100O B.1005060o 50 100 150 200 250 30000 50 100 150 200 250 300Temperature (C)Temperature (C)Volume vs. Temperature of a GasVolume vs. Temperature of a Gas180180160140140E 120OC. 100O D. 100600 500 100 150 200 250 30080 100 150 200 250 300Temperature (C)Temperature (c)

Chemistry
1 answer:
solmaris [256]4 years ago
5 0
Graph D.

Charles's law states that at the same pressure, the Volumen of a gas is proportional to its temperature (absolute temperature).

This is

V = K T, where K is the constant of proportionallity.

You can also write it in the form

V1 / V2 = T1/ Ts

When Temperature rise Volumen rise in a proportional way. If Temperature doubles Volumen doubles, if Tempearature is decreases to on third, Volume will decrease to one third.
You might be interested in
Use the periodic table to determine the electron configuration for aluminum (AI) and arsenic (As) in
Harlamova29_29 [7]

Answer:

Aluminum; [Ne]3s²3p¹

Arsenic; [Ar]3d¹⁰4s²4p³

Explanation:

<em>Aluminum</em>

From the periodic table, we have that aluminum, Al, is located in period 3, and group 3A of the periodic table

Therefore, the noble gas that comes before aluminum in the periodic table is neon Ne

The electronic configuration of aluminum is 1s²2s²2p⁶3s²3p¹

The electronic configuration of neon is 1s²2s²2p⁶

Therefore, the electronic configuration of aluminum in noble gas notation (Ne) is therefore;

[Ne]3s²3p¹

<em>Arsenic</em>

Arsenic is located after argon, Ar on the periodic table

The electronic configuration of arsenic is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p³

The electronic configuration of argon is 1s²2s²2p⁶3s²3p⁶

The electronic configuration of arsenic in noble gas notation (Ar) is given as follows;

[Ar]3d¹⁰4s²4p³

4 0
3 years ago
A 75 g piece of gold (Au) at 1000 K is dropped into 200 g of H2O at 300K in an insulatedcontainer at 1 bar. Calculate the temper
Arturiano [62]

Answer:

the final temperature is T final = 308 K

Explanation:

since all heat released by gold is absorbed by water

Q gold + Q water = Q surroundings =0 (insulated)

Assuming first that no evaporation of water occurs , and denoting g as gold and w as water , then

Q gold = m g*cp g* ( T final - T initial g)

Q gold = m w*cp w* ( T final - T initial w)

where

m= mass

cp = specific heat capacity

T final = final temperature

T initial g and T initial w =  initial temperature of gold and water respectively

thus

Q gold + Q water = 0

m g*cp g* ( T final - T initial g) + m w*cp w* ( T final - T initial w) =0

m g*cp g* T final + m w*cp w* T final =  m g*cp g* T initial g+ m w*cp w* T initial w

T final = (m g*cp g* T initial g+ m w*cp w* T initial w)/(m g*cp g+ m w*cp w)

replacing values and assuming cp w = 1 cal/gK = 4.816 J/gK and cp g = 0.129 J/gK (from tables), then

T final =  (75 g*0.129 J/gK* 1000 K + 200 g * 4.816 J/gK * 300 K )/(75 g*0.129 J/gK*+ 200 g * 4.816 J/gK ) = 308 K

T final = 308 K

since T boiling water = 373 K and T final = 308 K , we confirm that water does not evaporate

therefore the final temperature is T final = 308 K

3 0
3 years ago
The amount of a chemical solution is measured to be 2 liters.
irinina [24]
2 liters may be 1.5 to 1.9 rounded up to 2 or 2.1 or 2.4 rounded down to 2.

2 - 1.5 = 0.5

percent error = (absolute error / quantity) * 100

percent error = 0.5/2 * 100% = 0.25 * 100% = 25%

Choice C. 25%.
3 0
3 years ago
Questioned document examiners prefer to work with copies of a questioned document in order to avoid damage to the original
gladu [14]
I think it is a False
4 0
3 years ago
The movement of fluid materials caused by density differences
Dovator [93]
This movement is known as convection or convection currents. This occurs due to the fact that warmer fluid is of lower density than colder fluid. This causes warmer fluid to rise and colder fluid to sink. This creates circulatory currents within the body of the fluid.
8 0
3 years ago
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