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2 years ago

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Chemistry

1 answer:

dem82 [27]2 years ago

3 0

The number of molecules of gases in each of the 3 vessels is the same.

<h3>Number of moles</h3>

The first vessel contains 2g of $H_2$ gas:

Number of molecules in 2 g = 2/2 = 1 mole

The second vessel contains 32 g of $O_2$ gas:

Number of molecules = 32/32 = 1 mole

The third vessel contains 44 g of $CO_2$ gas:

Number of molecules = 44/44 = 1 mole

Thus, the 3 vessels contain the same number of moles of gases.

More on the number of moles can be found here: brainly.com/question/12513822

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In a chemical reaction, the difference between the potential energy of the products of the potential energy of the reactants is

Svetradugi [14.3K]

Your question looks a bit incomplete as you have the same contents in options a) and d). According to your list, I can't see the correct answer, but I can give you one.The difference between the potential energy of the products of the potential energy of the reactants is equal to the enthalpy of the reaction.

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3 years ago

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A chunk of copper has a volume of 1.45 mL and a mass of 12.93 grams. What is the density of the chunk of copper?

natta225 [31]

Answer:

$Density = 8.92 \ g/mL$

Explanation:

The equation for density is:

$Density = \frac{mass}{volume}$

We plug in the given values:

$Density = \frac{12.93 \ g}{1.45 \ mL}$

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When the valves are opened and the gases are allowed to mix at a constant temperature, what is the distribution of atoms in each

jek_recluse [69]

Answer:

Equal number of atoms of each gas in each container

Explanation:

When the valves opened, the two contaienrs become one and the gases beging to mix by diffusion. This phenomenom is produced by the differeces of concentration of a gas between two points of the container.

The gases will continue diffunding util their concentration in both containers are equal.

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3 years ago

A gamma ray photon has an energy of 4.75 x 10-14 joules. What is the frequency of this radiation?

Rama09 [41]

The frequency of the radiation is equal to $7.17 \times 10^{19}$ Hertz.

<u>Given the following data:</u>

Photon energy = $4.75 \times 10^{-14}$ Joules

To find the frequency of this radiation, we would use the Planck-Einstein equation.

Mathematically, the Planck-Einstein relation is given by the formula:

$E = hf$

<u>Where:</u>

h is Planck constant.

f is photon frequency.

Substituting the given parameters into the formula, we have;

$4.75 \times 10^{-14} = 6.626 \times 10^{-34} \times F\\\\F = \frac{4.75 \times 10^{-14}}{6.626 \times 10^{-34}}$

Frequency, F = $7.17 \times 10^{19}$ Hertz

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