Answer:
Lengths. of. Naphthalene. Figure 3.20 shows that there are two equivalent ... all the carbon–carbon bonds of benzene are identical and are intermediate in length ... A typical carbon–carbon single bond has a length of 1.54 Å, and a double ... of how resonance can be used to explain or predict experimental observations.Explanation:
Answer:
A model or simulation is only as good as the rules used to create it. It is very difficult to create an entirely realistic model or simulation because the rules are based on research and past events. The main disadvantage of simulations is that they aren't the real thing.
Explanation:
Answer:
The volume will be 89.6875 ml
Explanation:
So to count this we will use a single proportion.
0.0640 mol - 1000 ml
5.74×10−3 mol - x ml
x ml=5.74×10−3 mol*1000 ml/0.0640 mol=89.6875 ml
Answer:
Safety goggles and chemical fume hoods
Explanation:
Answer:
It is equal to Avogadro's number (NA), namely 6.022 x1023. If we have one mole of water, then we know that it will have a mass of 2 grams (for 2 moles of H atoms) + 16 grams (for one mole O atom) = 18 grams.
Explanation:
The question is not very much clear.
If you are asking for molecules then 1 mole water= 6.023 * 10^23
If you are asking for atoms then 1 mole water= 6.023 * 10^23 * 3
If you are asking for particles then,
So, in your example you would have one mole of water molecules. If you dissociated those water molecules, than you would end up with 2 moles of hydrogen atoms, and one mole of oxygen atoms.
I hope that was helpful!
H=1 proton,1 electron
O=8 protons,8 neutrons and 8 electrons
total particles in one H2O molecule-28
total no. of particles in 1 mole of water- 6.023 * 10^23 * 28
