No of mole = reacting mass/ molar mass
No of mole = 0.06/56
No of mole = 0.00107mol....
Or...
1mole of iron contain 56gmol¯¹
:-x mole is contained in 0.06g
Porata
And you'll have..
x = 0.06/56
x = 0.00107mol.....
Answer:
Bromohydrin and chlorohydrin are examples of halohydrins (where X = Br or Cl).
Answer:
c.
Explanation:
One of the main differences between an atom and an element is that an atom can be combined but an element cannot be combined. There are many combinations of atoms that make up different gases, liquids, and solids each with a unique makup. For example, water is made up of two hydrogen atoms and one oxygen atom (H20). Elements are made up of only the same type of atom. For example, the element Hydrogen can only contain hydrogen atoms, while the element Carbon can only contain carbon atoms.
Answer:
4.90 moles of
will produce (9.8) moles of
,
(4.90) moles of
and
(39.2) moles of ![O^{2-}](https://tex.z-dn.net/?f=O%5E%7B2-%7D)
Explanation:
From the question we are told that
The number of moles of is ![n = 4.90 \ mols](https://tex.z-dn.net/?f=n%20%3D%20%204.90%20%20%5C%20mols)
The formation reaction of
is
From the reaction we see that
1 mole of
is formed by 2 moles of
1 mole of
and 4 ![O^{2-}](https://tex.z-dn.net/?f=O%5E%7B2-%7D)
This implies that
4.90 moles of
will produce (2 * 4.90) moles of
,
(1 * 4.90) moles of
and
(8 * 4.90) moles of ![O^{2-}](https://tex.z-dn.net/?f=O%5E%7B2-%7D)
So
4.90 moles of
will produce (9.8) moles of
,
(4.90) moles of
and
(39.2) moles of ![O^{2-}](https://tex.z-dn.net/?f=O%5E%7B2-%7D)
Answer:
V₂ = 4.7 L
Explanation:
Given data:
Initial volume = 5.0 L
Initial pressure = 1.50 atm
Final pressure = 1240 mmHg (1240/760 = 1.6 atm)
Final volume = ?
Solution:
P₁V₁ = P₂V₂
V₂ = P₁V₁ / P₂
V₂ = 1.50 atm ×5.0 L/1.6 atm
V₂ = 7.5 atm. L /1.6 atm
V₂ = 4.7 L