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madreJ [45]
2 years ago
13

A car is moving at a rate of 72km/hr . How far does the car move when it stops after 4 seconds?

Physics
2 answers:
oee [108]2 years ago
8 0

Answer:

<em>The car will stop after 4 seconds after moving the distance of 0.08km.</em>

Explanation:

<em>The </em><em> </em><em>reading</em><em> </em><em>above</em><em> </em><em>it </em><em>clearly </em><em>states </em><em>that</em><em> </em><em>a</em><em> </em><em>car </em><em>is </em><em>moving</em><em> at</em><em> </em><em>a </em><em>speed </em><em>of </em><em> </em><em>7</em><em>2</em><em>K</em><em>m</em><em>/</em><em>hr.</em><em> </em><em>And </em><em>it </em><em>asking</em><em> </em><em>for</em><em> </em><em>the</em><em> </em><em>distance</em><em> </em><em>the </em><em>car </em><em>move</em><em> </em><em>when</em><em> </em><em>it </em><em>stops </em><em>after</em><em> </em><em>4</em><em> </em><em>seconds</em><em>.</em><em> </em>

<em>Looking</em><em> at</em><em> </em><em>speed</em><em> </em><em>formula</em><em> </em><em>,</em><em> </em><em>speed</em><em>=</em><em>distance</em><em>÷</em><em>t</em><em>i</em><em>m</em><em>e</em><em>.</em>

<em>But</em><em> </em><em>in</em><em> </em><em>this</em><em> </em><em>problem</em><em> </em><em>we </em><em>I </em><em>finding</em><em> </em><em>distance,</em><em> </em><em>so </em><em>in </em><em>speed</em><em> </em><em>formula</em><em> </em><em>make </em><em>distance</em><em> </em><em>the </em><em>subject</em><em>.</em>

<h3><em>Therefore</em><em> </em><em>distance</em><em> </em><em>=</em><em> </em><em>speed</em><em> </em><em>×</em><em> </em><em>time</em></h3>

<em>Before</em><em> </em><em>going</em><em> </em><em>ahead</em><em> </em><em>you</em><em> </em><em>should</em><em> </em><em>have</em><em> </em><em>this </em><em>in </em><em>mind </em><em>the </em><em>unit</em><em> for</em><em> </em><em>distance</em><em> </em><em>is </em><em>Km </em><em>and</em><em> </em><em>m </em><em>.</em><em> </em><em>Our </em><em>speed </em><em>is </em><em>in </em><em>Km/</em><em>hr </em><em>but </em><em>our </em><em>time</em><em> is</em><em> </em><em>in </em><em>second</em><em>.</em><em> </em><em>In </em><em>this</em><em> </em><em>case</em><em> </em><em>change</em><em> </em><em>4</em><em> </em><em>seconds</em><em> to</em><em> </em><em>hour </em><em>which </em><em>is</em><em> </em><em>0</em><em>.</em><em>0</em><em>0</em><em>1</em><em>1</em><em>1</em><em> </em><em>hr </em><em>.</em><em>you </em><em>change</em><em> </em><em>second</em><em> </em><em>to</em><em> </em><em>hour</em><em> </em><em>because</em><em> </em><em>hr </em><em>will</em><em> </em><em>cancel</em><em> </em><em>hr </em><em>when </em><em>solving</em><em> </em><em>for</em><em> </em><em>distance</em><em> </em><em>giving</em><em> </em><em>distance</em><em> </em><em>unit</em><em> </em><em>Km</em>

<em>Distance</em><em> </em><em>=</em><em> </em><em>speed</em><em> </em><em>×</em><em> </em><em>time</em>

<em>Distance</em><em>=</em><em> </em><em>7</em><em>2</em><em>k</em><em>m</em><em>/</em><em>hr </em><em>×</em><em> </em><em>0</em><em>.</em><em>0</em><em>0</em><em>1</em><em>1</em><em>1</em><em> </em><em>hr </em>

<em>hour </em><em>cancel</em><em> </em><em>hour</em>

<em>Distance= 72km</em><em> </em><em>×</em><em> </em><em>0</em><em>.</em><em>0</em><em>0</em><em>1</em><em>1</em><em>1</em>

<em>Distance </em><em>=</em><em> </em><em>0</em><em>.</em><em>0</em><em>8</em><em>k</em><em>m</em>

<em>Therefore</em><em> the</em><em> </em><em>car</em><em> </em><em>will</em><em> </em><em>stop</em><em> </em><em>after </em><em>4</em><em> </em><em>seconds</em><em> </em><em>after</em><em> </em><em>moving</em><em> </em><em>the</em><em> </em><em>distance</em><em> </em><em>of </em><em>0</em><em>.</em><em>0</em><em>8</em><em>k</em><em>m</em><em>.</em>

<em>Please</em><em> mark</em><em> brainliest</em><em>.</em>

kari74 [83]2 years ago
5 0

conversion :

72 km/h = 72 × (1000/3600) = 20 m/s

so, in 4 seconds it travel

  • 4 × 20 = 80 meters = 0.08 km
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