Answer:
s=4.44 m
Explanation:
Given that
Coefficient of the kinetic friction ,μ = 0.13
Initial velocity ,u= 3.4 m/s
Final velocity of the box ,v= 0 m/s
The acceleration due to friction force
a= - μ g
Now by putting the values in the above equation
a= - 0.13 x 10 ( take g= 10 m/s²)
a= - 1.3 m/s²
We know that
v²= u ² + 2 a s
s=distance
a=acceleration
v=final speed
u=initial speed
Now by putting the values in the above equation
0²= 3.4² - 2 x 1.3 x s
s=4.44 m
The distance cover by box will be 4.44 m.
The chemical bonds alow it to pass to the other object.
There is a sharp distinction between ionic and covalent bonds when the geometric arrangements of atoms in compounds are considered. In essence, ionic bonding is nondirectional, whereas covalent bonding is directional.
We have to use the equation speed=distance/time.
We want the average speed in second so we have to change the minutes into seconds. We can do this by multiplying the minutes by 60 (60seconds in 1 minute). 60x1.4= 84 seconds.
Speed=distance/time, distance is 82 and time is 84 so speed=82/84
Average speed = 0.98ms^-1 (2dp)
