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3 years ago

Question 1

Physics

1 answer:

mestny [16]3 years ago

6 0

Answer:

false

A hypothesis states a presumed relationship between two variables in a way that can be tested with empirical data. ... The cause is called the independent variable; and the effect is called the dependent variable.

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The loudness of a sound will be determined by its

adoni [48]

Answer:

By its amplitude.

Explanation:

loudness is sound intensity & intensity depends on square of amplitude. for example higher the amplitude higher the intensity which means higher the loudness.

4 0

3 years ago

Number of protons and electrons and atomic mass for a given element

faltersainse [42]

Explanation:

You can simply subtract the atomic number from the mass number in order to find the number of neutrons. If the atom is neutral, the number of electrons will be equal to the number of protons.

Remember!

1. Your mass number is the total number of neutrons and protons within the atom.

2. Your atomic number is the amount of protons within the atom.

3. For neutral atoms, the electron number is the same as the atomic number.

5 0

3 years ago

A 3 kg mass object is pushed 0.6 m into a spring with spring constant 210 N/m on a frictionless horizontal surface. Upon release

Aleksandr-060686 [28]

Answer with Explanation:

We are given that

Mass of spring,m=3 kg

Distance moved by object,d=0.6 m

Spring constant,k=210N/m

Height,h=1.5 m

a.Work done to compress the spring initially= $\frac{1}{2}kx^2=\frac{1}{2}(210)(0.6)^2=37.8J$

By conservation law of energy

Initial energy of spring=Kinetic energy of object

$37.8=\frac{1}{2}(3)v^2$

$v^2=\frac{37.8\times 2}{3}$

$v=\sqrt{\frac{37.8\times 2}{3}}$

v=5.02 m/s

c.Work done by friction on the incline, $w_{friction}=P.E-spring \;energy$

$W_{friction}=3\times 9.8\times 1.5-37.8=6.3 J$

3 0

3 years ago

The amount of power required to move an object can be increased without changing the

VLD [36.1K]

Answer:

Yes it is possible to increase the power with out changing the amount of work.

Explanation:

The power is defined by the amount of power divided by the time. This time is the one needed to do the work. We can understand this issue by analyzing an example with numeric values.

Work = 500 [J]

Time = 5 [s]

Power will be:

$Power=\frac{500}{5} \\Power=100 []watt]\\$

Now if we change the time to 2 seconds:

$Power = 500 [J]/2[s]\\Power = 250 [watt]\\$

As we can see, the power was increased without the need to change the work.

3 0

4 years ago

How far does light travel in the time it takes sound to go 1 cm?

aksik [14]

Sound travels at speed v=343 m/s, therefore the time the sound takes to cover a distance of
$S= 1 cm=0.01 m$
is
$t= \frac{S}{v}= \frac{0.01 m}{343 m/s}=2.9 \cdot 10^{-5} s$

Light travels at speed $c=3 \cdot 10^8 m/s$ , therefore the distance it travels during the same time t is
$S=ct=(3 \cdot 10^8 m/s)(2.9 \cdot 10^{-5} s)=8746 m=8.75 km$

6 0

3 years ago