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Arturiano [62]
2 years ago
15

Consider the reaction below. Upper N a superscript plus, plus upper C subscript 2 upper H subscript 3 upper O subscript 2 supers

cript minus (a q) plus upper H superscript plus, plus upper C l superscript minus right arrow upper N a superscript plus, plus upper C l superscript minus plus upper H upper subscript 2 upper H subscript 3 upper O subscript 2. Which is the net ionic equation for the reaction? Upper H superscript plus, plus upper C l superscript minus right arrow upper H upper C l. Upper N a superscript plus, plus upper C l superscript minus right arrow upper N a upper C l. Upper N a superscript plus, plus upper C subscript 2 upper H subscript 3 upper o subscript 2 superscript minus (a q) plus upper H superscript plus, right arrow upper N a upper C subscript 2 upper H subscript 3 upper O subscript 2. Upper C subscript 2 upper h subscript 3 upper O subscript 2 superscript minus (a q) plus upper H superscript plus right arrow upper H upper C subscript 2 upper H subscript 3 upper O subscript 2.
Chemistry
1 answer:
Brums [2.3K]2 years ago
5 0

No reaction occurs since all the ions appear on both sides of the equation, therefore, no product is formed.

<h3>What is a net ionic equation?</h3>

A net ionic equation is an equation in which the ions which appear on both sides of an ionic equation known as spectator ions are removed leaving only the products formed and the ions involved in their formation.

The equation of reaction is given below as follows:

  • Na^{+} + C_{2}H_{3}O_{2}^{-} + H^{+} + Cl^{-}\rightarrow Na^{+}+ Cl^{-} +C_{2}H_{3}O_{2}^{-} +  H^{+}

The ions all appear on both sides of the equation, therefore, no product is formed.

Therefore, no reaction occurs.

Learn more about net ionic equation at: brainly.com/question/19705645

#SPJ1

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Find the initial temperature of 45.0g of water if its final Temperature after submerging a metal with the mass of 8.5g is 22.0°C
Korolek [52]

The initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.

<em>"Your question is not complete, it seems to be missing the following information;"</em>

the specific heat capacity of the metal is 0.45 J/g⁰C.

The given parameters;

  • <em>mass of water, </em>m_w<em> = 45 g</em>
  • <em>final temperature of the water, </em>t_w<em> = 22 ⁰C</em>
  • <em>mass of the metal, m = 8.5 g</em>
  • <em>initial temperature of the metal, t = 82 ⁰C.</em>
  • <em>specific heat capacity of the metal, c = 0.45 J/g⁰C.</em>

The initial temperature of the water will be calculated by applying the principle of conservation of energy;

<em>heat gained by water = heat lost by metal</em>

Q_{water} = Q_{metal}

m_wc_w \Delta t_w = mc\Delta t

where;

c_w <em>is the specific heat capacity of the water = 4.184 J/g⁰C.</em>

<em />

<em>Substitute the given values;</em>

45 x 4.184 x (22 - t) = 8.5 x 0.45 x (85 - 22)

4142.16  - 188.28t = 240.98

188.28t  = 4142.16  - 240.98

188.28t  = 3901.18

t = \frac{3901.18}{188.28} \\\\t = 20.7 \ ^0 C

Thus, the initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.

Learn more here:brainly.com/question/15345295

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3 years ago
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