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barxatty [35]
3 years ago
5

State whether the error introduced by each of the following problems would result in a high or a low value for the Cu recovery o

r would not affect the results. Explain. a. Some of the copper nitrate solution splashes out of the beaker in step 1. _____________
Chemistry
1 answer:
vampirchik [111]3 years ago
5 0

Answer:

Low value for copper recovery

Explanation:

The percentage recovery is obtained from;

Percent recovery = amount of substance you actually collected / amount of substance you were supposed to collect × 100

Note that the fact that some of the copper nitrate solution splashed out of the beaker means that some amount copper has been lost from the system. This loss of copper leads to a lower value of copper recovered from solution.

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true.

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Look at the properties of Oxygen and Silicon - the two most abundant elements in the Earth's crust - by clicking on their symbols on the Periodic Table.

Explanation:

7 0
3 years ago
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1.12g H2 is allowed to react with 9.60 g N2, producing 1.23 g NH3.
andriy [413]

Answer:

A. m_{NH_3}^{theo} =1.50gNH_3

B. Y=82.2\%

Explanation:

Hello!

In this case, since the undergoing chemical reaction between nitrogen and hydrogen is:

N_2+3H_2\rightarrow 2NH_3

Thus we proceed as follows:

A. Here, we first need to compute the moles of ammonia yielded by each reactant, in order to identify the limiting one:

n_{NH_3}^{by \ H_2}=1.12gH_2*\frac{1molH_2}{2.02gH_2}*\frac{2molNH_3}{3molH_2}=0.370molNH_3\\\\  n_{NH_3}^{by \ N_2}=1.23gN_2*\frac{1molN_2}{28.02gN_2}*\frac{2molNH_3}{1molN_2}=0.0878molNH_3

Thus, since nitrogen yields the fewest moles of ammonia, we realize it is the limiting reactant, so the theoretical yield, in grams, of ammonia is:

m_{NH_3}^{theo}=0.0878mol*\frac{17.04gNH_3}{1molNH_3} =1.50gNH_3

B. Finally, since the actual yield of ammonia is 1.23, the percent yield turns out:

Y=\frac{1.23gNH_3}{1.50gNH_3} *100\%\\\\Y=82.2\%

Best regards!

5 0
3 years ago
Write the net ionic equation for the equilibrium that is established when potassium hypochlorite is dissolved in water.
oee [108]
Potassium hypochlorite when dissolved in water would dissociate into ions namely the potassium ions and the hypochlorite ions. Furthermore, hypochlorite ions would interact with water molecules and would decompose further. The dissociation reactions are as follows:

KClO <=> K+ + ClO-
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Adding the two reactions, would give

KClO + ClO- + H2O = K+ + HOCl + OH- + ClO- 

The two ClO- ions in both sides would cancel giving us the net ionic equation:

KClO + H2O = K+ + HOCl + OH-
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3 years ago
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Explanation:

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