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2 years ago

Which of these is a covalent compound?

Chemistry

2 answers:

AysviL [449]2 years ago

6 0

Answer : The correct option is, (A) $NO_2$

Explanation :

Ionic bond : It is defined as the bond which is formed by complete transfer of electrons from one atom to another atom.

The ionic compound is formed between a metal and a non-metal.

Covalent bond : It is defined as the bond that is formed when sharing of electrons takes place between the atoms.

The covalent compound is formed between two non-metals.

(a) $NO_2$

It is a covalent compound in which nitrogen and oxygen are non-metals. The $NO_2$ is formed when one nitrogen atom share their electrons with two oxygen atoms.

(b) $LiCl$

It is an ionic compound in which lithium is a metal and chlorine is a non-metal. The $LiCl$ is formed by the complete transfer of electrons.

(c) $AlCl_3$

It is an ionic compound in which aluminum is a metal and chlorine is a non-metal. The $AlCl_3$ is formed by the complete transfer of electrons.

(d) $Na_2S$

It is an ionic compound in which sodium is a metal and sulfur is a non-metal. The $Na_2S$ is formed by the complete transfer of electrons.

Hence, the covalent compound is $NO_2$

OLga [1]2 years ago

4 0

A. NO2 because the elements are both nonmetals.

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Which polymer structure should be used if a strong and heat - resistant adhesive is required?

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Cross-linked polymers are strong and heat - resistant hence they can be used for this purpose.

A polymer is obtained by the combination of small molecules called monomers. A polymer consists of a regular repeating unit of small molecules called monomers.

A cross-linked polymer is a polymer in which covalent bonds are used to join polymer chains together. Cross-linked polymers are strong and heat - resistant hence they can be used for this purpose.

Learn more: brainly.com/question/17638582

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2 years ago

One reaction involved in the conversion of iron ore to the metal is FeO(s) + CO(g) → Fe(s) + CO2(g) Use Hess’s Law to calculate

Ugo [173]

Answer:

$\delta H_{rxn} = -66.0 \ kJ/mole$

Explanation:

Given that:

$3FeO_3_{(s)}+CO_{(g)} \to 2Fe_3O_4_{(s)} +CO_{2(g)} \ \ \delta H = -47.0 \ kJ/mole -- equation (1) \\ \\ \\ Fe_2O_3_{(s)} +3CO_{(g)} \to 2FE_{(s)} + 3CO_{2(g)} \ \ \delta H = -25.0 \ kJ/mole -- equation (2) \\ \\ \\ Fe_3O_4_{(s)} + CO_{(g)} \to 3FeO_{(s)} + CO_{2(g)} \ \delta H = 19.0 \ kJ/mole -- equation (3)$

From equation (3) , multiplying (-1) with equation (3) and interchanging reactant with the product side; we have:

$3FeO_{(s)} + CO_{2(g)} \to Fe_3O_4_{(s)} + CO_{(g)} \ \delta H = -19.0 \ kJ/mole -- equation (4)$

Multiplying (2) with equation (4) ; we have:

$6FeO_{(s)} + 2CO_{2(g)} \to 2Fe_3O_4_{(s)} + 2CO_{(g)} \ \delta H = -38.0 \ kJ/mole -- equation (5)$

From equation (1) ; multiplying (-1) with equation (1); we have:

$2Fe_3O_4_{(s)} +CO_{2(g)} \to 3FeO_3_{(s)}+CO_{(g)} \ \ \delta H = 47.0 \ kJ/mole -- equation (6)$

From equation (2); multiplying (3) with equation (2); we have:

$3 Fe_2O_3_{(s)} +9CO_{(g)} \to 6FE_{(s)} + 9CO_{2(g)} \ \ \delta H = -75.0 \ kJ/mole -- equation (7)$

Now; Adding up equation (5), (6) & (7) ; we get:

$6FeO_{(s)} + 2CO_{2(g)} \to 2Fe_3O_4_{(s)} + 2CO_{(g)} \ \delta H = -38.0 \ kJ/mole -- equation (5)$

$2Fe_3O_4_{(s)} +CO_{2(g)} \to 3FeO_3_{(s)}+CO_{(g)} \ \ \delta H = 47.0 \ kJ/mole -- equation (6)$

$3 Fe_2O_3_{(s)} +9CO_{(g)} \to 6FE_{(s)} + 9CO_{2(g)} \ \ \delta H = -75.0 \ kJ/mole -- equation (7)$

$FeO \ \ \ + \ \ \ CO \ \ \to \ \ \ \ Fe_{(s)} + \ \ CO_{2(g)} \ \ \ \delta H = - 66.0 \ kJ/mole$

$\delta H_{rxn} = \delta H_1 + \delta H_2 + \delta H_3$ (According to Hess Law)

$\delta H_{rxn} = (-38.0 + 47.0 + (-75.0)) \ kJ/mole$

$\delta H_{rxn} = -66.0 \ kJ/mole$

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3 years ago

If you only wanted to increase the particle motion of a gas without increasing any of its other properties, which would the most

andrey2020 [161]

Answer:

Explanation:

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2 years ago

A pressure cooker contains 5.68 L of air at a temperature of 390 4K if the absolute pressure of the air in the pressure cooker i

Cloud [144]

Answer:

3.59x10⁻⁴ mol

Explanation:

Assuming ideal behaviour we can solve this problem by using the PV=nRT formula, where:

P = 205 Pa

V = 5.68 L

n = ?

R = 8314.46 Pa·L·mol⁻¹·K⁻¹

T = 390.4 K

We input the data given by the problem:

205 Pa * 5.68 L = n * 8314.46 Pa·L·mol⁻¹·K⁻¹ * 390.4 K

And solve for n:

n = 3.59x10⁻⁴ mol

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2 years ago

Which two kinds of information describe weather and not climate?

Fynjy0 [20]

Answer: b & c

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