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Stolb23 [73]
2 years ago
14

1.- What type of parabola is this?

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
4 0

Answer:

<u>Part 1</u>

<u>Sideways or "horizontal" parabola</u> with a horizontal axis of symmetry.

<u>Part 2</u>

The vertex is the turning point:  (-3, 1)

<u>Part 3</u>

Vertex form of a horizontal parabola:

x=a(y-k)^2+h    

where:

  • (h, k) is the vertex
  • a is some constant
    If a > 0 the parabola opens to the right.
    If a < 0 the parabola opens to the left.

Point on the curve:  (-1, 2)

Substituting the vertex and the found point into the formula and solving for a:

\implies -1=a(2-1)^2-3

\implies -1=a-3

\implies a=2

<u>Part 4</u>

Equation for the given parabola in vertex form:

x=2(y-1)^2-3

Equation in standard form:

x=2y^2-4y-1

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[ \boxed{\bold{Final \ Answer}} ]

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