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cricket20 [7]
2 years ago
12

An electronic defibrillator used on heart attack victims works by delivering charge stored in a capacitor. If the device utilize

s a
Physics
1 answer:
Vilka [71]2 years ago
6 0

The energy stored in the capacitor at given capacitance and voltage is determined as 396.5 J.

<h3>Energy stored in the capacitor</h3>

The energy stored in the capacitor is calculated as follows;

E = ¹/₂CV²

where;

V is the voltage

E = ¹/₂ x 13 x 10⁻⁶ x (7.81 x 10³)²

  • C is the capacitance
  • V is the voltage

E = ¹/₂ x 13 x 10⁻⁶ x (7.81 x 10³)²

E = 396.5 J

Thus, the energy stored in the capacitor at given capacitance and voltage is determined as 396.5 J.

The complete question is below

An electronic defibrillator used on heart attack victims works by delivering charge stored in a capacitor. If the device utilizes a 13.0 μF capacitor charged to 7.81 × 103 V, what is the energy stored in the capacitor?

Learn more about capacitor here: brainly.com/question/13578522
#SPJ4

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monochromatic light from a distant source is incident on a slit 0.75 mm wide. on screen 2 m away, the distance from the central
hjlf

Displacement from the center line for minimum intensity is 1.35 mm , width of the slit  is 0.75 so  Wavelength of the light  is 506.25.

<h3>How to find Wavelength of the light?</h3>

When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.

This is a straightforward situation in which we can apply the

Fraunhofer single slit diffraction equation:

y = mλD/a

Where:

y = Displacement from the center line for minimum intensity =  1.35 mm

λ =  wavelength of the light.

D = distance

a = width of the slit = 0.75

m = order number = 1

Solving for λ

λ = y + a/ mD

Changing the information that the issue has provided:

λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2  

=5.0625 *10^-7 = 506.25

so

Wavelength of the light 506.25.

To learn more about Wavelength of the light refer to:

brainly.com/question/15413360

#SPJ4

5 0
1 year ago
n astronaut who weighs 800 N on the surface of the earth lifts off from planet Zuton in a space ship. The free-fall acceleration
ANTONII [103]

Answer: 0.29 kN

Explanation:

We have the following data:

W_{E}=800 N is the weight of the astronaut on Earth

g_{E}=9.8 m/s^{2} is the free fall acceleration due gravity on Earth (directed downwards)

g_{Z}=3 m/s^{2} is the free fall acceleration due gravity on Zuton (directed downwards)

a=0.5 m/s^{2} is the acceleration of the spaceship at litoff (directed upwards)

We have to find the <u>magnitude of the force</u> F the space ship exerts on the astronaut.

Firstly, we have to know weight has a direct relation with the mass and the acceleration due gravity. In the case of Earth is:

W_{E}=mg_{E} (1)

Where m is the mass of the atronaut.

Isolating m:

m=\frac{W_{E}}{g_{E}} (2)

m=\frac{800 N}{9.8 m/s^{2}} (3)

m=81.63 kg (4)

Now that we know the mass of the astronaut, we can find its weight on Zuton:

W_{Z}=mg_{Z} (5)

W_{Z}=(81.63 kg)(3 m/s^{2}) (6)

W_{Z}=244.89 N (7)

Then, we can calculate the force the space ship exerts on the astronaut by the following equation:

F-W_{Z}=m.a (8)

Isolating F:

F=m.a+W_{Z} (9)

F=(81.63 kg)(0.5 m/s^{2})+244.89 N (10)

F=285.7 N \frac{1 kN}{1000 N}=0.285 kN (11)

Finally:

F=0.285 kN \approx 0.29 kN

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I think the answer to your question is a galaxy. 
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A car is traveling at a constant speed of 12m/s , when the driver accelerates the car reaches a speed of 26 m/s in 6s what is th
DaniilM [7]

Acceleration = (change in speed) / (time for the change)

Change in speed = (end speed) - (start speed)

Change in speed = (26 m/s) - (12 m/s) = 14 m/s

Time for the change = 6 s

Acceleration = (14 m/s) / (6 s)

Acceleration = (14/6) (m/s²)

<em>Acceleration = 2.33 m/s²</em>

7 0
4 years ago
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