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nadezda [96]
3 years ago
7

Two waves on one string are described by the wave functions

Physics
1 answer:
alex41 [277]3 years ago
3 0

Answer:

a) y_{R} (1.00,1.00) = -0.546\,cm, b) y_{R} (1.00,0.50) = -4.311\,cm, c) y_{R} (0.50,0.00) = 2.278\,cm

Explanation:

The principle of superposition points out that:

y_{R}(x,t) = \Sigma^{n}_{i=1} y_{i} (x,t)

Then, the results are:

a) y_{R} (1.00, 1.00) = y_{1} (1.00,1.00) + y_{2} (1.00,1.00)

y_{R} (1.00,1.00) = -0.546\,cm

b) y_{R} (1.00, 0.50) = y_{1} (1.00,0.50) + y_{2} (1.00,0.50)

y_{R} (1.00,0.50) = -4.311\,cm

c) y_{R} (0.50, 0.00) = y_{1} (0.50,0.00) + y_{2} (0.50,0.00)

y_{R} (0.50,0.00) = 2.278\,cm

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When a circuit is arranged in parallel
attashe74 [19]

Answer:

A. There are multiple paths that electrons can take through the circuit, and it is possible for the electron to pass through one circuit component but not another.

Explanation:

Parallel arrangement of components in an electric circuit puts different parts of the circuit on different branches. In a parallel connection, there are multiple paths for the electrons to take, and it is possible for electrons to pass through on circuit component without going through another. This is the reason why If there is a break in one branch of the circuit, electrons can still flow in other branches, and the same reason why one bulb going off in your home does prevent the other components in your home from coming on (your home is wired in a parallel electric circuit).

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An object moves 20 m east in 30 s and then returns to its starting point taking an additional 50 s. If west is chosen as the pos
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The sign associated with the average velocity of the object is negative.

<h3>Average velocity of the object</h3>

The average velocity of the object is calculated as follows;

Average velocity = (v1 + v2)/2

v1 = -20/30 = -0.667 m/s

v2 = 20/50 = 0.4 m/s

Average velocity = (-0.667 + 0.4)/2

Average velocity  = -0.134 m/s

Thus, the sign associated with the average velocity of the object is negative.

Learn more about average velocity here: brainly.com/question/6504879

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2 years ago
A 100 kg roller coaster comes over the first hill at 2 m/sec (vo). The height of the first hill (h) is 20 meters. See roller dia
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For the 100 kg roller coaster that comes over the first hill of height 20 meters at 2 m/s, we have:

1) The total energy for the roller coaster at the <u>initial point</u> is 19820 J

2) The potential energy at <u>point A</u> is 19620 J

3) The kinetic energy at <u>point B</u> is 10010 J

4) The potential energy at <u>point C</u> is zero

5) The kinetic energy at <u>point C</u> is 19820 J

6) The velocity of the roller coaster at <u>point C</u> is 19.91 m/s

1) The total energy for the roller coaster at the <u>initial point</u> can be found as follows:

E_{t} = KE_{i} + PE_{i}

Where:

KE: is the kinetic energy = (1/2)mv₀²

m: is the mass of the roller coaster = 100 kg

v₀: is the initial velocity = 2 m/s

PE: is the potential energy = mgh

g: is the acceleration due to gravity = 9.81 m/s²

h: is the height = 20 m

The<em> total energy</em> is:

E_{t} = KE_{i} + PE_{i} = \frac{1}{2}mv_{0}^{2} + mgh = \frac{1}{2}*100 kg*(2 m/s)^{2} + 100 kg*9.81 m/s^{2}*20 m = 19820 J

Hence, the total energy for the roller coaster at the <u>initial point</u> is 19820 J.

   

2) The <em>potential energy</em> at point A is:

PE_{A} = mgh_{A} = 100 kg*9.81 m/s^{2}*20 m = 19620 J

Then, the potential energy at <u>point A</u> is 19620 J.

3) The <em>kinetic energy</em> at point B is the following:

KE_{A} + PE_{A} = KE_{B} + PE_{B}

KE_{B} = KE_{A} + PE_{A} - PE_{B}

Since

KE_{A} + PE_{A} = KE_{i} + PE_{i}

we have:

KE_{B} = KE_{i} + PE_{i} - PE_{B} =  19820 J - mgh_{B} = 19820 J - 100kg*9.81m/s^{2}*10 m = 10010 J

Hence, the kinetic energy at <u>point B</u> is 10010 J.

4) The <em>potential energy</em> at <u>point C</u> is zero because h = 0 meters.

PE_{C} = mgh = 100 kg*9.81 m/s^{2}*0 m = 0 J

5) The <em>kinetic energy</em> of the roller coaster at point C is:

KE_{i} + PE_{i} = KE_{C} + PE_{C}            

KE_{C} = KE_{i} + PE_{i} = 19820 J      

Therefore, the kinetic energy at <u>point C</u> is 19820 J.

6) The <em>velocity</em> of the roller coaster at point C is given by:

KE_{C} = \frac{1}{2}mv_{C}^{2}

v_{C} = \sqrt{\frac{2KE_{C}}{m}} = \sqrt{\frac{2*19820 J}{100 kg}} = 19.91 m/s

Hence, the velocity of the roller coaster at <u>point C</u> is 19.91 m/s.

Read more here:

brainly.com/question/21288807?referrer=searchResults

I hope it helps you!

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What is weightlessness ? Mention its condition​
kolbaska11 [484]

Answer:

Weightlessness, condition experienced while in free-fall, in which the effect of gravity is canceled by the inertial (e.g., centrifugal) force resulting from orbital flight. The term zero gravity is often used to describe such a condition.

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